1.2 moles of Neon = ? grams
Mole Conversions (Moles-Grams-Molecules)

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•
Chemistry
•
10th Grade
•
Hard
Cassandra Williams
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10 questions
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1.
FLASHCARD QUESTION
Front
Back
24 grams
Answer explanation
To find the mass of 1.2 moles of Neon, use the molar mass of Neon, which is approximately 20 grams/mole. Multiply: 1.2 moles x 20 g/mole = 24 grams. Thus, the correct answer is 24 grams.
2.
FLASHCARD QUESTION
Front
5.6 moles of sodium bromide = ? grams
Back
576 g
Answer explanation
To find the mass of sodium bromide, multiply the number of moles (5.6) by its molar mass (102.9 g/mol). Thus, 5.6 moles x 102.9 g/mol = 576 g, making 576 g the correct answer.
3.
FLASHCARD QUESTION
Front
Convert 28g O₂ to moles.
Back
0.875 moles
Answer explanation
To convert grams to moles, use the formula: moles = mass (g) / molar mass (g/mol). The molar mass of O2 is 32.0 g/mol. Thus, 28.0 g O2 = 28.0 g / 32.0 g/mol = 0.875 moles. Therefore, the correct answer is 0.875 moles.
4.
FLASHCARD QUESTION
Front
9.44 moles of AlCl₃ contains:
Back
5.68x10²⁴ molec AlCl₃
Answer explanation
To find the number of molecules in 9.44 moles of AlCl3, multiply by Avogadro's number (6.022 x 10^23). Thus, 9.44 moles x 6.022 x 10^23 molec/mole = 5.68 x 10^24 molec AlCl3, making the correct choice 5.68x10^24 molec AlCl3.
5.
FLASHCARD QUESTION
Front
Moles of magnesium in 3.01x10²² atoms?
Back
0.050 moles Mg
Answer explanation
To find moles from atoms, use Avogadro's number (6.02x10^23). Divide 3.01x10^22 by 6.02x10^23: 3.01x10^22 / 6.02x10^23 = 0.050 moles Mg. Thus, the correct answer is 0.050 moles Mg.
6.
FLASHCARD QUESTION
Front
Molecules in 9.4 moles of ibuprofen?
Back
5.66x10⁴
Answer explanation
To find the number of molecules in 9.4 moles of ibuprofen, multiply by Avogadro's number (6.022 x 10^23). Thus, 9.4 moles x 6.022 x 10^23 molecules/mole = 5.66 x 10^24 molecules, making 5.66x1024 the correct answer.
7.
FLASHCARD QUESTION
Front
Molar mass of Ba(C₂H₃O₂)₂
Back
255.3 g/mol
Answer explanation
To calculate the molar mass of Ba(C2H3O2)2, sum the atomic masses: Ba (137.3 g/mol) + 2*(C (12.0 g/mol)*2 + H (1.0 g/mol)*3 + O (16.0 g/mol)*2) = 255.3 g/mol. Thus, the correct answer is 255.3 g/mol.
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