Inference

Inference

Assessment

Flashcard

Mathematics

10th - 12th Grade

Practice Problem

Hard

Created by

Wayground Content

FREE Resource

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12 questions

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1.

FLASHCARD QUESTION

Front

Hypotheses for determining if more than 50% of households gave a charitable donation last year.

Back

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2.

FLASHCARD QUESTION

Front

Interpretation of 95% confidence level in a survey of 100 samples, each with 1,200 US citizens, about optimism in the economy.

Back

We would expect about 95 of the 100 confidence intervals to contain the proportion of all citizens of the United States who are optimistic about the economy.

3.

FLASHCARD QUESTION

Front

What is the appropriate method for constructing a one-sample confidence interval to estimate the population mean surface area of the species of maple leaves, and why is the method appropriate?

Back

The t-interval is appropriate, because the population standard deviation is not known.

4.

FLASHCARD QUESTION

Front

Smallest sample size for 95% confidence and 0.02 margin of error in estimating TV viewers of a program? Options: 40, 50, 100, 1700, 2500

Back

2500

5.

FLASHCARD QUESTION

Front

99% confidence interval for the proportion of all employees at the company who own an electric car, given 15 out of 500 sampled own one.

Back

Media Image

6.

FLASHCARD QUESTION

Front

Which procedure is most appropriate for investigating whether an association exists between gender and the number of friends a person has on a social media Web site?

Media Image

Back

A chi-square test of independence

7.

FLASHCARD QUESTION

Front

On the day before an election in a large city, each person in a random sample of 1,000 likely voters is asked which candidate he or she plans to vote for. Of the people in the sample, 55 percent say they will vote for candidate Taylor. A margin of error of 3 percentage points is calculated. Which statement is appropriate?

Back

The sample proportion minus the margin of error is greater than 0.50, which provides evidence that more than half of all likely voters plan to vote for candidate Taylor.

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