Linear Word Problems

Linear Word Problems

Assessment

Flashcard

Created by

Quizizz Content

Mathematics

8th Grade

Hard

Student preview

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17 questions

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1.

FLASHCARD

Front

Bob has $150 in his savings account and saves $40 per month. Which equation represents the amount Bob has in his account after x months?

Back

y = 40x + 150

2.

FLASHCARD

Front

A holiday meal costs $12.50 a person plus a delivery fee of $30. Which equation represents the amount a holiday meal costs, including delivery, for x people?

Back

y = 12.5x + 30

3.

FLASHCARD

Front

Easy Car Rental charges $8.50 an hour plus a rental fee of $25.50. Which equation represents the total charges for x hours?

Back

y = 25.5 + 8.5x

4.

FLASHCARD

Front

Jerry has $20 and makes $7 per hour. Which equation represents the total amount of money Jerry has after working x hours? Options: y = 7x + 20, y = 7 + 20x, y = 20 + 7

Back

y = 7x + 20

5.

FLASHCARD

Front

Sonya has $40 in her lunch account and pays $2 each day to eat lunch. Which equation can be used to find the amount of money Sonya has left on her account after x days? Options:

y = 40 + 2x

,

y = - 2x + 40

,

y = 2 + 40x

,

y = 2 - 40x

Back

y = - 2x + 40

6.

FLASHCARD

Front

Will spent $26 on eTunes music with a start-up cost of $7.95 and $0.95 per song. How many songs did he download?

Back

19 songs

7.

FLASHCARD

Front

Admission to the fair is $5 and the cost per ride is $0.50. How many rides can you go on if you have $20?

Back

30 rides

8.

FLASHCARD

Front

A man is climbing down from 100 feet high descending 30 feet per minute. What is the equation?

Back

y = - 30x + 100

9.

FLASHCARD

Front

The total cost (y) at an amusement park can be modeled by y=1.5x+20 where x is the number of rides you ride. What is the price to ride 10 rides?

Back

35

10.

FLASHCARD

Front

Sandra has a $20 iTunes gift card and spends $3 each month. Which equation can be used to find how much money Sandra has on her gift card after x months? Options: y = 3x + 20, y = 3 + 20x, y = -3x + 20, y = -20x + 3

Back

y = -3x + 20

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