Special Right Triangles
Flashcard
•
Mathematics
•
8th Grade
•
Practice Problem
•
Hard
+2
Standards-aligned
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10 questions
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1.
FLASHCARD QUESTION
Front
Find the value of y.
Back
3 sqrt. 2/2
Answer explanation
45-45-90
1-1-sqrt-2
leg to hypotenuse: multiply by sqrt 2
Legs are congruent so
(3sqrt2/2)
Tags
CCSS.HSG.SRT.C.8
2.
FLASHCARD QUESTION
Front
A diagonal of a square mirror is 10 inches long. What is the length, in inches, of each side of the mirror?
Back
5 sqrt 2 inches
Answer explanation
1:1:sqrt2
you know the hypotenuse
divide 10 by sqrt 2
10/sqrt2
Tags
CCSS.8.G.B.8
3.
FLASHCARD QUESTION
Front
A 12 foot ladder is leaning against the side of a building forming a right triangle. The angle formed by the ladder and the ground is 60 degrees. What is the distance, in feet, of the bottom of the ladder from the base of the wall?
Back
6
Answer explanation
30-60-90
1:sqrt3:2
you know the longest side and need the shortest side
so divide by 2
12/2
Tags
CCSS.HSG.SRT.C.8
4.
FLASHCARD QUESTION
Front
What is the distance from Point A to Point B in feet? Options: 4 sqrt 3, 12, 12 sqrt 3, 24
Back
12 sqrt 3
Answer explanation
30-60-90
1:sqrt3:2
the 6 is the shortest side because it is across from the smallest angle
the hypotenuse is across from the right angle
point A to the right angle is the medium side
so multiply by sqrt 3
so 6sqrt3
to get all the way across multiply the 6sqrt3(2)
12 sqrt 3
Tags
CCSS.HSG.SRT.C.8
5.
FLASHCARD QUESTION
Front
Triangle DEF is an equilateral triangle with side length of 12 inches. What is the height of triangle DEF?
Back
6 sqrt 3
Answer explanation
If you draw the line from the vertex to the opposite side you create a 30-60-90 triangle
use the pattern 1:sqrt3:2
the 12 is the largest side
to find the smallest divide by 2, so 6
the medium is the small times sqrt3
6 sqrt 3
Tags
CCSS.HSG.CO.C.11
6.
FLASHCARD QUESTION
Front
Find the value of u.
Back
4
Answer explanation
30-60-90
1:sqrt3:2
small side is 2 the
large side is opposite right angles so 4
and the medium side is opposite the 60 so v which would be 2 sqrt 3
Tags
CCSS.HSG.SRT.C.8
7.
FLASHCARD QUESTION
Front
A path goes diagonally through a park created from an old city block. If the short end of the block is 72 yards, how long is the path inside the park?
Back
144 yds
Answer explanation
The exterior angle and the interior angle create a linear pair.
180-150=30 creating a 30-60-90 triangle.
This is a 30-60-90 triangle, so the short leg is 1/2 the length of the diagonal. The short leg is 72 yards, multiply by 2.
So the diagonal is 72(2)=144
Tags
CCSS.HSG.SRT.D.10
CCSS.HSG.SRT.D.11
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