Front

Equation: y + 1 = -3 (x - 5)
Find the slope of the line containing the point (5, -1).

Back

-3

Tags

CCSS.8.EE.B.5

Front

Which of these represents point-slope form of a linear equation? Options: y - y₁ = m(x - x₁), Ax + By = C, y = mx + b, y=kx

Back

y - y₁ = m(x - x₁)

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3

Front

For the equation 
y - 4 = -1/3(x - 7), 
what are the coordinates for the point? Options: (4, 7), (-7, - 4), (7, 4), (-4, -7)

Back

(7, 4)

Front

Equation of the line in Point-Slope form through (10,5) with slope -3

Back

y - 5 = -3(x - 10)

Front

Equation of the line y + 5 = -3(x - 6) in slope intercept form?

Back

y = -3x+13

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3

Front

Write the equation in point-slope form for the line that contains the points (-2, -3), (4, 3)

Back

y + 3 = 1(x + 2)

Front

Back

-1

Tags

CCSS.8.EE.B.5

Front

Which of these represents slope-intercept form of a linear equation? Options: y - y₁ = m(x-x₁), Ax + By = C, y = mx + b, y=kx

Back

y = mx + b

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3

Front

Which of these represents standard form of a linear equation? Options: y - y₁ = m(x-x₁), Ax + By = C, y = mx + b, y=kx

Back

Ax + By = C

Front

Equation of a line with slope m = 3 through point (1,-5) in point-slope form

Back

Answer explanation

To write the equation, plug in the point and slope!