Front

Solve for x:
2(3x + 4) + 2 = 4 + 3x

Back

-2

Front

8x + 2 + 3x + 5 = x + 12

Back

1/2

Front

Which of these equations has infinitely many solutions? Options: 6x + 2 = 2(3x + 1), 6x + 2 = 5x + 2, 6x + 2 = 6x + 3, ?

Back

6x + 2 = 2(3x + 1)

Front

What step would you take to solve this equation? Options: Multiply both sides of the equation by 2, Divide both sides of the equation by 2, Add 2 to both sides of the equation, Subtract 2 from both sides of the equation

Back

Multiply both sides of the equation by 2

Front

Find the error in the problem: 19 - 2k = 3k - 1
     +3k   +3k
19 + 1k = -1
-19           -19
k = -20

Back

Instead of adding 3k they should subtract 3k