Solving Quadratics

Front

Solutions to the equation: (x-3)(x+2)=0

Back

x=3, -2

Front

Solve by completing the square.
x² + 4x= 12

Back

x = -6 and 2

Front

Solve by completing the square: x² − 10x - 11 = 0

Back

x = −1 and 11

Front

ax²+bx+c=0 is the standard form of a quadratic equation.

Back

True

Front

Determine the values of a, b, and c for the quadratic equation: 4x² – 8x = 3

Back

a = 4, b = -8, c = -3

Front

Solve
a² + 2a - 24 = 0

Back

a = -6, 4

Front

Identify the 'a' value: y = 16x² -8x -24

Back

16

Front

Identify the 'b' value in the equation: y = 16x² -8x -24

Back

-8

Front

Identify the 'c' value: y = 16x² -8x -24

Back

-24

Front

What is the discriminant? Options: b²-4ac, b²/2a, 4ac, b²±4ac

Back

b²-4ac