In an ideal gas, if everything else is held constant, doubling the volume will ________ the pressure.
Gas Laws

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Chemistry
•
10th Grade
•
Hard
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19 questions
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1.
FLASHCARD QUESTION
Front
Back
halve
Answer explanation
Since nRT cannot change, neither can PV. If you multiply V by 2, you would have to multiply P by 1/2 to keep the right side constant.
2.
FLASHCARD QUESTION
Front
In an ideal gas, if everything else is held constant, tripling the pressure will ________ the Kelvin temperature.
Back
triple
Answer explanation
If you multiply P by 3, you would have to multiply T by 3 as well in order to keep the right side equal to the left.
3.
FLASHCARD QUESTION
Front
Back
4.
FLASHCARD QUESTION
Front
You stand at the end of a long hallway. At the other end, your classmate releases equal amounts of two gases, carbon-dioxide and chlorine. Which one reaches you first?
Back
CO2
Answer explanation
Lighter gases diffuse faster.
5.
FLASHCARD QUESTION
Front
According to kinetic molecular theory: at constant temperature, increasing the volume will decrease the pressure because...
Back
the gas particles must travel farther from wall to wall.
Answer explanation
farther travel = fewer collisions per second
In kinetic molecular theory:
pressure = collisions per second between gas and walls of container
temperature = average kinetic energy of gas molecules (as measured by temperature)
6.
FLASHCARD QUESTION
Front
According to kinetic molecular theory: at constant volume, increasing the temperature will increase the pressure because...
Back
the gas particles are moving faster; faster = more collisions-per-second.
Answer explanation
increased temp = increased kinetic energy
In kinetic molecular theory:
pressure = collisions per second between gas and walls of container
temperature = average kinetic energy of gas molecules (as measured by temperature
7.
FLASHCARD QUESTION
Front
The pressure of a gas at 22 °C goes from 3 atm to 6 atm, with volume held constant. What is its new temperature?
Back
317 °C
Answer explanation
The Kelvin temperature doubles.
22 °C = 295 K
295*2 = 590
590 – 273 = 317 °C
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