Quadratics

Quadratics

Assessment

Flashcard

Mathematics

8th Grade

Practice Problem

Hard

CCSS
HSF-IF.C.7A, HSA-REI.B.4B

Standards-aligned

Created by

Wayground Content

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19 questions

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1.

FLASHCARD QUESTION

Front

What is the vertex for the parabola represented by the equation
y = 2(x + 3)2 - 8?

Back

(-3, -8)

2.

FLASHCARD QUESTION

Front

Equation for the given graph: f(x) = (x - 2)2 - 1, f(x) = (x + 2)2 - 1, f(x) = -(x + 2)2 - 1, f(x) = -(x - 2)2 - 1

Media Image

Back

f(x) = (x + 2)2 - 1

Tags

CCSS.HSF-IF.C.7A

3.

FLASHCARD QUESTION

Front

Identify the vertex and whether the graph opens up or down.

Media Image

Back

(1, 4); opens down

Tags

CCSS.HSF-IF.C.7A

4.

FLASHCARD QUESTION

Front

Equation for a quadratic function that opens downward with vertex (-4, 7):
f(x)= -(x-4)2+7, f(x)= (x+4)2+7, f(x)= -(x+4)2+7, f(x)= (x-4)2+7

Back

f(x)= -(x+4)2+7

5.

FLASHCARD QUESTION

Front

How does the graph of g(x)=3x2 compare to the quadratic parent function f(x)=x2?

Back

The graph of g(x) is narrower than the graph of f(x).

6.

FLASHCARD QUESTION

Front

Identify the correct vertex form, vertex, and y-intercept for f(x)= x2+6x-1. Options: y=(x+3)2-10
Vertex: (-3, -10)
y-intercept: (0, -1), y=(x+3)2+19
Vertex: (-3, 19)
y-intercept: (0, 1), y=(x+3)2+1
Vertex: (-3, -1)
y-intercept: (0, -10), y=(x-3)2+10
Vertex: (3, 10)
y-intercept: (0, -1)

Back

y=(x+3)2-10
Vertex: (-3, -10)
y-intercept: (0, -1)

7.

FLASHCARD QUESTION

Front

A rocket was launched from a balcony 10 feet from the ground. The rocket modeled the equation h(t)= -t2 + 6t + 10, where t represent time in seconds and h(t) represents the height in feet. What is the maximum height the rocket will reach before it starts to go back down?

Back

19 feet

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