Solving Quadratics

Front

Find the zeros of this quadratic. Options: b=4/5, b=3, b=4, b=-3, b=1/5

Back

b=4/5, b=-3

Tags

CCSS.HSA-REI.B.4B

Front

Solve by factoring!

Back

-2, 4

Tags

CCSS.HSA-REI.B.4B

Front

What are the zeros?

Back

x= 0 and x= 4

Tags

CCSS.HSA-SSE.B.3B

CCSS.HSF-IF.C.8A

Front

Solve by factoring: x² - 9x + 20 = 0

Back

x = 4 and x = 5

Tags

CCSS.HSA-REI.B.4B

Front

Zeroes of a quadratic function

Back

x-intercepts

Tags

CCSS.HSF-IF.C.7A

Front

Zeros of x²+9x+14

Back

-2, -7

Front

What are the solutions of this graph? Options: -2 and 3, -1/2 and -6, -2 and -6, 3 and -6

Back

-2 and 3

Front

Given the zeros below, what are the factors? Options: (3x-2) (4x-1), (2x-3) (1x-4), (3x-2) (1x-4), (2x-3) (4x-1)

Back

(2x-3) (4x-1)

Tags

CCSS.HSF-IF.C.7C

Front

What is this formula?

Back

This is the quadratic formula.

Tags

CCSS.HSA-REI.B.4B

Front

Is Suzie correct in solving the equation (x - 2)(x + 6) = 2 by setting x - 2 = 0 and x + 6 = 0? Why or why not?

Back

No, she did factor correctly, but she can't use the zero product property as shown.

Tags

CCSS.HSA-REI.B.4B