ALGEBRA- 1°

Front

5(X +2)-8(X-9)+4(2X +8)=4(X+40)+10

Back

56

Front

Reducir: A= - [ 5(a + b) - 4(a- b)+ 3] - (a- 9b -2a)

Back

-3

Front

Resolver:

Back

0

Front

Calcular :

Back

1

Front

Resolver:

Back

23

Front

Back

Front

Hallar : A x B x C . Si:

Back

24

Front

Hallar: A + B + C

Back

-103

Front

B = [ 6 (2 -x)+4(x - 4)]-[4-3(x+2)]=10

Back

12

Front

D= 20[ 2(2 - x)- 3(2 - x)]=10[ 4(3 -x) - 2(x - 4)]

Back

3