A.2A Domain and Range Word Problems

A.2A Domain and Range Word Problems

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Flashcard

Mathematics

9th Grade

Hard

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12 questions

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1.

FLASHCARD QUESTION

Front

A student worked out at a gym continuously for 50 minutes. The graph shows the remaining percentage of the workout as a linear function of x, the time in minutes.
Which answer choice best describes the domain and range of the function for this situation? Options: Domain: all real numbers greater than or equal to 0 and less than or equal to 100. Range: all real numbers greater than or equal to 0 and less than or equal to 50. Domain: {-2} Range: {100} Domain: all real numbers greater than or equal to 0 and less than or equal to 50. Range: all real numbers greater than or equal to 0 and less than or equal to 100. Domain: {100} Range: {-2}

Back

Domain: all real numbers greater than or equal to 0 and less than or equal to 50. Range: all real numbers greater than or equal to 0 and less than or equal to 100.

2.

FLASHCARD QUESTION

Front

The daily cost of hiring a plumber, y, to work x hours on a repair project can be modeled using a linear function. The plumber charges a fixed cost of $80 plus an additional cost of $45 per hour. The plumber works a maximum of 8 hours per day. For one day of work, what is the range of the function for this situation?

Back

3.

FLASHCARD QUESTION

Front

What is the range of the function f(x)=20x+4 for x pairs of 20 lb plates added to a 4 lb barbell? Options: {0, 1, 2, 3, 4, 5, 6,}, {4, 24, 44, 64, 84, 104, 124}, {0, 2, 4, 6}, {4, 44, 84, 124}

Back

{4, 24, 44, 64, 84, 104, 124}

4.

FLASHCARD QUESTION

Front

Domain of the function c=34.95u+6.25 for 8 ≤ u ≤ 12

Back

5.

FLASHCARD QUESTION

Front

Range of function f(c) = c/20 for no more than 5,000 cars transported daily?

Back

The set of all integers from 0 to 250

6.

FLASHCARD QUESTION

Front

Domain of the function f(x)=40+10x for gym membership fees.

Back

0, 1, 2, 3.....

7.

FLASHCARD QUESTION

Front

What is the range of the function f(x)=40+10x?

Back

$40, $50, $60.....

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