Solving Quadratics by Factoring Practice

Front

Which equation matches standard form of a quadratic? Options: ax + by = c, y = a(x - h)² + k, y = ax² + bx + c, y = mx + b

Back

y = ax² + bx + c

Front

What are the roots of the function?

Back

x = -4, 1

Front

6x² + 17x + 12 = 0

Back

x = -4/3, x = -3/2

Front

2x² - 3x - 2 = 0

Back

x = -1/2, x = 2

Front

What should you do first in solving this equation?
x² + 6x - 13 = 3

Back

Make it equal 0 by subtracting 3 on each side

Front

Convert x²-6x+9 to factored form and identify the solution.

Back

(x-3)(x-3); x=3

Front

Solve
4m² - 100 = 0

Back

m=5, -5

Front

True or false: The solutions, roots, x-intercepts, and zeros of a quadratic equation are all the same thing.

Back

True

Front

Factor: x² + 11x + 24

Back

(x + 8)(x + 3)

Front

Find the zeros of this quadratic: b=4/5, b=3, b=4, b=-3, b=1/5, b=3, b=4/5, b=-3

Back

b=4/5, b=-3