Solving Quadratics by Factoring and Quadratic Formula

Front

(x-5)(x+6)=0

Back

{5,-6}

Tags

CCSS.HSA-REI.B.4B

Front

What is the first step in solving (x + 2)(x - 3) = 0?

Back

Set each binomial factor equal to zero

Tags

CCSS.HSA-REI.B.4B

Front

Which equation matches these solutions? x=5,-7
Options: (x+5)(x-7)=0, (x-5)(x+7)=0, (x+5)(x+7)=0, (x-5)(x-7)=0

Back

(x-5)(x+7)=0

Tags

CCSS.HSA-REI.B.4B

Front

Solve the quadratic equation.

Back

-2, 4

Tags

CCSS.HSA-REI.B.4B

Front

Solve 2x² + 2x - 12 = 0 using the quadratic formula.

Back

2, -3

Tags

CCSS.HSA-REI.B.4B

Front

Solve the quadratic equation.

Back

-4, 2

Tags

CCSS.HSA-REI.B.4B

Front

Convert x²+6x+9=0 to factored form and identify the solution.

Back

(x+3)(x+3)=0; x=-3

Tags

CCSS.HSA-REI.B.4B

Front

Find the zeros of this quadratic.

Back

b=4/5, b=-3

Tags

CCSS.HSA-REI.B.4B

Front

Solve by factoring:
x² - 9x = 0

Back

0, 9

Tags

CCSS.HSA-REI.B.4B

Front

Factors AND find the solutions of x² + 2x – 3 = 0

Back

(x - 1)(x + 3); x=1, x=-3

Tags

CCSS.HSA-REI.B.4B