EJHS - Solving Quadratics by Factoring

Front

Solve by factoring: x² = 7x + 18

Back

9 and -2

Tags

CCSS.HSA-REI.B.4B

Front

Solve by factoring: 2x² + 7x + 6 = 0

Back

x = -3/2 and x = -2

Tags

CCSS.HSA-REI.B.4B

Front

(x-5)(x+6)=0

Back

{5,-6}

Tags

CCSS.HSA-REI.B.4B

Front

What is the first step in solving (x + 2)(x - 3) = 0?

Back

Set each binomial factor equal to zero

Tags

CCSS.HSA-REI.B.4B

Front

Factors and solutions of x² + 2x – 3 = 0

Back

Factors: (x - 1)(x + 3); Solutions: x=1, x=-3

Tags

CCSS.HSA-REI.B.4B

Front

Solve by factoring:
x² - 9x = 0

Back

0, 9

Tags

CCSS.HSA-REI.B.4B

Front

What property would you use to solve the following?
(x-3)(x+2)=0
Options: Commutative Property, Associative Property, Zero Product Property, Inverse Property

Back

Zero Product Property

Tags

CCSS.HSA-REI.B.4B

Front

(2x - 2)(5x + 5) = 0

Back

x = -1 or x = 1

Tags

CCSS.HSA-REI.B.4B

Front

What should you do first in solving this equation?
x² + 6x - 13 = 3
Options: Get factored form, Find two numbers which add to make 6 and multiply to make -13, Make it equal 0 by subtracting 3 on each side, Type it all in a calculator.

Back

Make it equal 0 by subtracting 3 on each side

Tags

CCSS.HSA-REI.B.4B

Front

Solve by factoring: n² - 2n = 0

Back

n = 2 and 0

Tags

CCSS.HSA-REI.B.4B