AP CS A Unit 3 Review

AP CS A Unit 3 Review

Assessment

Flashcard

Computers

11th - 12th Grade

Practice Problem

Hard

Created by

ZenonTS ZenonTS

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17 questions

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1.

FLASHCARD QUESTION

Front

What is output by the following code? Options: 11, 15, 31, error

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Back

11

Answer explanation

The x * 3 is equal to 30 so the first if runs and increments x (which is 10) by one. Then

since 11 is smaller than 31, it will not run the second if, thus printing 11

2.

FLASHCARD QUESTION

Front

Consider the following incomplete code segment. Consider the following potential replacements for /* missing code */ . Which of these replacements will cause the code segment to always print false ? Assume that Math is imported correctly into our program.Options: (int)(Math.random() * 10) + 20, (int)(Math.random() * 10) + 25, (int)(Math.random() * 10) + 30, (int)(Math.random() + 30)

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Back

(int)(Math.random() * 10) + 20

Answer explanation

Math.random() returns a random value between 0 (inclusive)

and 1 (exclusive). So Math.random()*10 + 20 can give values

between 20.0 and 29.9999... By typecasting the value to an int,

the decimal values are truncated, which gives a range from 20 to

29 inclusive, meaning it never returns 30, and false is always

printed as a result

3.

FLASHCARD QUESTION

Front

Given the variables, which boolean condition is true?
Options: a < b && a == b, a > b || a != b, a < b && a != b, b >= a && a >= b

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Back

b >= a && a >= b

Answer explanation

This is equivalent to a == b, which is true

4.

FLASHCARD QUESTION

Front

The following truth table matches which boolean condition? A && ( A || B ), A && ( A && B ), !A && ( A || !B ), A || ( A || B )

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Back

A || ( A || B )

Answer explanation

This is equivalent to A || B which the truth table reflects

5.

FLASHCARD QUESTION

Front

To test if a grade (represented by the double variable g) is a B (between 80 - inclusive - and 90 exclusive), what set of three symbols correctly fills in the blanks in the order they appear? Options: >=, &&, <; >=, ||, <; >, ||, <=; <=, &&, >

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Back

>=, &&, <

Answer explanation

We want inclusive of the lower bound and exclusive of the upper bound, so we

need to use >= and <, and we need both conditions to be true so we use &&

6.

FLASHCARD QUESTION

Front

Result of evaluating the expression with boolean variables x and y.

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Back

True only when x and y have different values.

Answer explanation

(x||y) - x or y must be true; && - and the next expression must be true; !(x&&y) - x and y can not both be true

7.

FLASHCARD QUESTION

Front

Consider the following code fragment, assume val is an int: Which of the following code fragments would have the same effect? Options: if (!(val == 50 || val < 0)), if (val == 50 || val > 0), if (val == 50 || val < 0), if (val == 50 && val < 0)

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Back

if (val == 50 || val < 0)

Answer explanation

When val is a negative value or 50, it should evaluate to true, this is the

proper use of De Morgan’s law (&& will change to ||)

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