Circles - Complete the Square
Flashcard
•
Mathematics
•
9th - 12th Grade
•
Practice Problem
•
Hard
Standards-aligned
Wayground Content
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15 questions
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1.
FLASHCARD QUESTION
Front
What is the standard form of a circle's equation?
Back
The standard form of a circle's equation is (x - h)² + (y - k)² = r², where (h, k) is the center of the circle and r is the radius.
Tags
CCSS.HSG.GPE.A.1
2.
FLASHCARD QUESTION
Front
How do you complete the square for the equation x² + 6x + y² - 12y + 20 = 0?
Back
To complete the square, rearrange the equation: (x² + 6x) + (y² - 12y) = -20. Then, complete the square for x and y: (x + 3)² - 9 + (y - 6)² - 36 = -20. This simplifies to (x + 3)² + (y - 6)² = 25.
Tags
CCSS.HSG.GPE.A.1
3.
FLASHCARD QUESTION
Front
What is the center of the circle given by the equation (x + 3)² + (y - 6)² = 25?
Back
The center of the circle is (-3, 6).
Tags
CCSS.HSG.GPE.A.1
4.
FLASHCARD QUESTION
Front
What is the radius of the circle given by the equation (x + 3)² + (y - 6)² = 25?
Back
The radius of the circle is 5, since r² = 25, thus r = √25 = 5.
Tags
CCSS.HSG.GPE.A.1
5.
FLASHCARD QUESTION
Front
How do you find the radius from the equation (x + 2)² + (y - 3)² = 36?
Back
The radius is found by taking the square root of the right side of the equation: r = √36 = 6.
Tags
CCSS.HSG.GPE.A.1
6.
FLASHCARD QUESTION
Front
What does the equation x² + y² + 6x - 2y + 1 = 0 represent?
Back
This equation represents a circle, which can be rewritten in standard form by completing the square.
Tags
CCSS.HSG.GPE.A.1
7.
FLASHCARD QUESTION
Front
What is the process to determine the center and radius from the equation x² + y² - 10x + 8y - 8 = 0?
Back
Rearrange the equation to group x and y terms, complete the square for both, and then rewrite in standard form to find the center (5, -4) and radius 7.
Tags
CCSS.HSG.GPE.A.1
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