equations Equations EQUATIONS

equations Equations EQUATIONS

Assessment

Flashcard

Mathematics

8th Grade

Hard

CCSS
6.EE.B.7, 7.EE.B.4A, 8.EE.C.7B

+1

Standards-aligned

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15 questions

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1.

FLASHCARD QUESTION

Front

What is the first step to solve the equation 7 + \frac{a}{3} = 5?

Back

Subtract 7 from both sides to isolate the term with 'a': \frac{a}{3} = 5 - 7.

Tags

CCSS.7.EE.B.4A

2.

FLASHCARD QUESTION

Front

How do you isolate 'a' in the equation \frac{a}{3} = -2?

Back

Multiply both sides by 3 to get a = -6.

Tags

CCSS.6.EE.B.7

3.

FLASHCARD QUESTION

Front

What is the solution to the equation 8w - 8 = -4w + 16?

Back

w = 2.

4.

FLASHCARD QUESTION

Front

What is the process to solve the equation m + 18 = -8?

Back

Subtract 18 from both sides to isolate 'm': m = -8 - 18.

Tags

CCSS.6.EE.B.7

5.

FLASHCARD QUESTION

Front

How do you solve the equation \frac{3}{5}h = 27?

Back

Multiply both sides by \frac{5}{3} to isolate 'h': h = 27 * \frac{5}{3}.

Tags

CCSS.6.EE.B.7

6.

FLASHCARD QUESTION

Front

What is the solution to the equation 3c + 5 = 23?

Back

Subtract 5 from both sides and then divide by 3: c = 6.

Tags

CCSS.7.EE.B.4A

7.

FLASHCARD QUESTION

Front

What does it mean to isolate a variable in an equation?

Back

To isolate a variable means to manipulate the equation so that the variable is on one side and all other terms are on the other side.

Tags

CCSS.7.EE.B.4A

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