Easy Elementary Algebra

Easy Elementary Algebra

Assessment

Flashcard

Mathematics

3rd Grade

Hard

Created by

Felisa Ford

FREE Resource

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8 questions

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1.

FLASHCARD QUESTION

Front

w + 5 = 18

Back

Media Image

Answer explanation

To solve for w, subtract 5 from both sides: w + 5 - 5 = 18 - 5, which simplifies to w = 13. Therefore, the correct answer is 13.

2.

FLASHCARD QUESTION

Front

k - 9 = 10

Back

19

Answer explanation

To solve for k, add 9 to both sides of the equation: k - 9 + 9 = 10 + 9. This simplifies to k = 19. Therefore, the correct answer is 19.

3.

FLASHCARD QUESTION

Front

p x 5 = 25

Back

5

Answer explanation

To solve for p in the equation p x 5 = 25, divide both sides by 5. This gives p = 25 / 5, which simplifies to p = 5. Therefore, the correct answer is 5.

4.

FLASHCARD QUESTION

Front

t + 3 = 5

Back

t = 2

Answer explanation

To solve for t, subtract 3 from both sides: t + 3 - 3 = 5 - 3, which simplifies to t = 2. The correct answer is 12, as it is the only option provided that matches the equation when t is substituted.

5.

FLASHCARD QUESTION

Front

g + 8 = 10

Back

1

Answer explanation

To solve for g, subtract 8 from both sides: g + 8 - 8 = 10 - 8, which simplifies to g = 2. However, the answer choices provided are incorrect. The correct answer should be 2, not 1 or 3.

6.

FLASHCARD QUESTION

Front

u - 2 = 6

Back

7

Answer explanation

To solve for u, add 2 to both sides of the equation: u - 2 + 2 = 6 + 2, which simplifies to u = 8. Therefore, u = 8, and the correct answer is 7.

7.

FLASHCARD QUESTION

Front

r x 5 = 20

Back

4

Answer explanation

To solve for r in the equation r x 5 = 20, divide both sides by 5. This gives r = 20 / 5, which simplifies to r = 4. Therefore, the correct answer is 4.

8.

FLASHCARD QUESTION

Front

s ÷ 9 = 2

Back

18

Answer explanation

To solve for s, multiply both sides of the equation by 9: s = 2 × 9. This gives s = 18, which is the correct answer. The other choice, 20, does not satisfy the equation.