Algebra 1 | EOC Practice Test

Front

What is the distance formula used to calculate the distance between two points in a coordinate plane?

Back

The distance formula is given by: \(d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\)

Tags

CCSS.HSG.GPE.B.7

Front

How do you find the midpoint between two points in a coordinate plane?

Back

The midpoint \(M\) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is calculated as: \(M = \left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right)\)

Tags

CCSS.HSG.GPE.B.6

Front

What is the slope of a line given two points \((x_1, y_1)\) and \((x_2, y_2)\)?

Back

The slope \(m\) is calculated using the formula: \(m = \frac{y_2 - y_1}{x_2 - x_1}\)

Tags

CCSS.8.EE.B.5

Front

What does it mean for a function to be linear?

Back

A function is linear if it can be expressed in the form \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept.

Tags

CCSS.8.F.B.4

CCSS.HSF.LE.A.2

Front

What is the significance of the y-intercept in a linear equation?

Back

The y-intercept is the point where the line crosses the y-axis, represented as \((0, b)\) in the equation \(y = mx + b\).

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3

Front

How do you convert a fraction to a decimal?

Back

To convert a fraction to a decimal, divide the numerator by the denominator.

Tags

CCSS.7.NS.A.2D

CCSS.8.NS.A.1

Front

What is the formula for calculating the area of a rectangle?

Back

The area \(A\) of a rectangle is calculated as: \(A = length \times width\)

Tags

CCSS.3.MD.C.7B

CCSS.4.MD.A.3

Front

What is the formula for calculating the perimeter of a rectangle?

Back

The perimeter \(P\) of a rectangle is calculated as: \(P = 2(length + width)\)

Tags

CCSS.4.MD.A.3

Front

What is the definition of a function in mathematics?

Back

A function is a relation that assigns exactly one output for each input from its domain.

Tags

CCSS.8.F.A.1

Front

What is the quadratic formula used for?

Back

The quadratic formula is used to find the solutions of a quadratic equation in the form \(ax^2 + bx + c = 0\) and is given by: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)

Tags

CCSS.HSA-REI.B.4B