VSEPR Theory

Front

Which one of the following is the correct bond angle between atoms adopting a trigonal planar geometry? 180°, 109.5°, 90°, 120°

Back

120°

Front

The atoms in a molecule of water adopt what kind of geometry?

Back

Bent

Front

Ammonia, NH₃, adopts a tetrahedral geometry. However, the non-bonding pair on the central nitrogen atom distorts the bond angle away from the expected 109.5°. Which of the following statements correctly describes how the bond angle is distorted?

Back

The actual bond angle is reduced: it is less than 109.5°

Front

When applying VSEPR theory to predict molecular shape, which of the following do we not need to take into account? Valence electrons occupying sigma bonding orbitals, Valence electrons occupying pi bonding orbitals, Valence electrons occupying non-bonding orbitals

Back

Valence electrons occupying non-bonding orbitals

Front

From the following possible responses, select those responses that give the combination of bonds that makes up a triple covalent bond: Two sigma bonds, Two pi bonds, One sigma bond and two pi bonds, Two sigma bonds and one pi bond.

Back

One sigma bond and two pi bonds

Front

Apply the VSEPR model to XeF4. Which molecular shape is consistent with the model? Options: Disphenoidal, Square planar, Tetrahedral, Square pyramidal

Back

Square planar

Front

For which of the following molecules would the VSEPR model predict a trigonal pyramidal structure? BeF2, BF3, PF3, CF4

Back

PF3

Front

Choose the molecule that is incorrectly matched with the electronic geometry about the central atom: CF₄ - tetrahedral, BeBr₂ - linear, H₂O - tetrahedral, PF₃ - pyramidal.

Back

H₂O - tetrahedral

Front

The F-S-F bond angles in SF₆ are ______.

Back

90^o and 120^o

Front

A (pi) bond is the result of the

Back

sidewise overlap of two parallel p orbitals.