Rolle's Theorem & mean value theorem

Rolle's Theorem & mean value theorem

Assessment

Flashcard

Mathematics

12th Grade

Hard

CCSS
HSF-IF.C.7B

Standards-aligned

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14 questions

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1.

FLASHCARD QUESTION

Front

What is Rolle's Theorem?

Back

Rolle's Theorem states that if a function is continuous on a closed interval [a, b], differentiable on the open interval (a, b), and F(a) = F(b), then there exists at least one c in (a, b) such that F'(c) = 0.

2.

FLASHCARD QUESTION

Front

What are the conditions for applying Rolle's Theorem?

Back

1. The function must be continuous on the closed interval [a, b]. 2. The function must be differentiable on the open interval (a, b). 3. The function values at the endpoints must be equal, i.e., F(a) = F(b).

3.

FLASHCARD QUESTION

Front

What is the Mean Value Theorem?

Back

The Mean Value Theorem states that if a function is continuous on a closed interval [a, b] and differentiable on the open interval (a, b), then there exists at least one c in (a, b) such that F'(c) = (F(b) - F(a)) / (b - a).

4.

FLASHCARD QUESTION

Front

How does Rolle's Theorem relate to the Mean Value Theorem?

Back

Rolle's Theorem is a special case of the Mean Value Theorem where F(a) = F(b). In this case, the average rate of change is zero, leading to at least one point where the derivative is also zero.

5.

FLASHCARD QUESTION

Front

What does it mean for a function to be continuous on an interval?

Back

A function is continuous on an interval if there are no breaks, jumps, or holes in the graph of the function within that interval.

Tags

CCSS.HSF-IF.C.7B

6.

FLASHCARD QUESTION

Front

What does it mean for a function to be differentiable on an interval?

Back

A function is differentiable on an interval if it has a derivative at every point in that interval, meaning it has a defined slope at every point.

7.

FLASHCARD QUESTION

Front

Provide an example of a function that satisfies the conditions of Rolle's Theorem.

Back

An example is F(x) = x^2 - 4 on the interval [2, 2]. Here, F(2) = F(2) = 0, and the function is continuous and differentiable.

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