Coordinate Algebra Unit 2 EOC Review

Front

What is the cost function for Peg's phone if it costs $25 plus $0.25 per minute?

Back

The cost function is C_P(m) = 25 + 0.25m, where m is the number of minutes.

Tags

CCSS.8.F.B.4

CCSS.HSF.LE.A.2

Front

What is the cost function for Larry's phone if it costs $35 plus $0.20 per minute?

Back

The cost function is C_L(m) = 35 + 0.20m, where m is the number of minutes.

Tags

CCSS.HSF-BF.A.1A

Front

How do you determine when Peg's phone costs more than Larry's phone?

Back

Set the cost functions equal: 25 + 0.25m > 35 + 0.20m and solve for m.

Front

What is the solution to the inequality 25 + 0.25m > 35 + 0.20m?

Back

The solution is m > 200 minutes.

Front

Back

It represents a region above the line with slope -3 and y-intercept 4.

Tags

CCSS.HSA.REI.D.12

Front

Back

It represents a region below the line with slope 1 and y-intercept -2.

Tags

CCSS.HSA.REI.D.12

Front

How do you identify the solution to the equation f(x) = g(x) from a table of values?

Back

Look for the x-value where the outputs of f(x) and g(x) are equal.

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Front

What is the profit formula for a business that invests in equipment and has production costs?

Back

Profit = Revenue - Costs, where Revenue = Selling Price * Quantity and Costs = Fixed Costs + Variable Costs * Quantity.

Front

If a product costs $0.90 to produce and sells for $1.50, what is the profit per unit?

Back

Profit per unit = Selling Price - Production Cost = 1.50 - 0.90 = $0.60.

Tags

CCSS.6.EE.B.6

Front

How do you calculate the break-even point for a business?

Back

Set the total revenue equal to total costs and solve for quantity.

Tags

CCSS.8.EE.C.7B