Composition Of Functions

Composition Of Functions

Assessment

Flashcard

Mathematics

12th Grade

Practice Problem

Hard

Created by

Wayground Content

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14 questions

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1.

FLASHCARD QUESTION

Front

Define composition of functions.

Back

The composition of functions is a process where one function is applied to the result of another function. If \( f(x) \) and \( g(x) \) are two functions, the composition is denoted as \( (f \circ g)(x) = f(g(x)) \).

2.

FLASHCARD QUESTION

Front

What is the formula for finding \( g(1) \) if \( g(x) = 4x - 3 \)?

Back

To find \( g(1) \), substitute 1 into the function: \( g(1) = 4(1) - 3 = 1 \).

3.

FLASHCARD QUESTION

Front

Calculate \( f(2) \) if \( f(x) = x^2 - 1 \).

Back

To find \( f(2) \), substitute 2 into the function: \( f(2) = 2^2 - 1 = 3 \).

4.

FLASHCARD QUESTION

Front

What is the result of \( [f \circ g](4) \) if \( f(x) = 2x^2 + 3x \) and \( g(x) = x - 1 \)?

Back

First, find \( g(4) = 4 - 1 = 3 \). Then, find \( f(3) = 2(3^2) + 3(3) = 18 + 9 = 27 \).

5.

FLASHCARD QUESTION

Front

How do you find \( f[g(h(24))] \) if \( f(x) = \frac{6}{7}x + 3 \), \( g(x) = \frac{2}{3}x - 1 \), and \( h(x) = \frac{1}{4}x + 6 \)?

Back

First, calculate \( h(24) = \frac{1}{4}(24) + 6 = 12 + 6 = 18 \). Then, \( g(18) = \frac{2}{3}(18) - 1 = 12 - 1 = 11 \). Finally, \( f(11) = \frac{6}{7}(11) + 3 = \frac{66}{7} + 3 = \frac{66}{7} + \frac{21}{7} = \frac{87}{7} \approx 12.43 \).

6.

FLASHCARD QUESTION

Front

What is the value of \( f[g(h(3))] \) if \( f(x) = x^2 - 2 \), \( g(x) = x + 9 \), and \( h(x) = -3x \)?

Back

First, calculate \( h(3) = -3(3) = -9 \). Then, \( g(-9) = -9 + 9 = 0 \). Finally, \( f(0) = 0^2 - 2 = -2 \).

7.

FLASHCARD QUESTION

Front

Explain the significance of the order in function composition.

Back

The order of composition matters because \( f(g(x)) \) is generally not the same as \( g(f(x)) \). The output of the first function becomes the input of the second.

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