What is the coefficient of kinetic friction (μk)?
AP Physics 1 Forces and Incline Plane Test

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Science
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12th Grade
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Hard
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1.
FLASHCARD QUESTION
Front
Back
The coefficient of kinetic friction (μk) is a dimensionless scalar value that represents the ratio of the force of kinetic friction between two bodies to the normal force pressing them together. It quantifies how easily one surface slides over another.
2.
FLASHCARD QUESTION
Front
What is the coefficient of static friction (μs)?
Back
The coefficient of static friction (μs) is a dimensionless scalar value that represents the ratio of the maximum static frictional force that must be overcome to start moving an object to the normal force acting on the object.
3.
FLASHCARD QUESTION
Front
How do you calculate the net force acting on an object?
Back
Net force (Fnet) is calculated using the formula: Fnet = Fapplied - Ffriction - Fgravity (if applicable). It is the vector sum of all forces acting on the object.
4.
FLASHCARD QUESTION
Front
What is the formula for calculating acceleration (a) using net force?
Back
Acceleration (a) can be calculated using Newton's second law: a = Fnet / m, where Fnet is the net force acting on the object and m is the mass of the object.
5.
FLASHCARD QUESTION
Front
What happens to the acceleration of an object if the net force is zero?
Back
If the net force acting on an object is zero, the object will either remain at rest or continue to move at a constant velocity, resulting in zero acceleration.
6.
FLASHCARD QUESTION
Front
What is the role of friction on an inclined plane?
Back
Friction on an inclined plane opposes the motion of an object sliding down the plane. It acts parallel to the surface and is influenced by the coefficient of friction and the normal force.
7.
FLASHCARD QUESTION
Front
How do you determine the normal force on an inclined plane?
Back
The normal force (N) on an inclined plane is calculated using the formula: N = m * g * cos(θ), where m is the mass of the object, g is the acceleration due to gravity, and θ is the angle of the incline.
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