Math 2-Unit 3 Midterm Review Day 1

Math 2-Unit 3 Midterm Review Day 1

Assessment

Flashcard

Mathematics

10th Grade

Hard

CCSS
HSA-REI.B.4B, HSF-IF.C.7A

Standards-aligned

Created by

Wayground Content

FREE Resource

Student preview

quiz-placeholder

14 questions

Show all answers

1.

FLASHCARD QUESTION

Front

What is the vertex of a parabola?

Back

The vertex of a parabola is the highest or lowest point on the graph, depending on its orientation. It can be found using the formula \( x = -\frac{b}{2a} \) for a quadratic equation in the form \( ax^2 + bx + c \).

2.

FLASHCARD QUESTION

Front

How do you find the roots of a quadratic equation?

Back

The roots of a quadratic equation can be found using the quadratic formula: \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).

Tags

CCSS.HSA-REI.B.4B

3.

FLASHCARD QUESTION

Front

What is the quadratic formula?

Back

The quadratic formula is used to find the solutions (roots) of a quadratic equation of the form \( ax^2 + bx + c = 0 \) and is given by \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).

Tags

CCSS.HSA-REI.B.4B

4.

FLASHCARD QUESTION

Front

What does the discriminant of a quadratic equation tell us?

Back

The discriminant, given by \( b^2 - 4ac \), indicates the nature of the roots: if positive, there are two distinct real roots; if zero, there is one real root; if negative, there are no real roots.

Tags

CCSS.HSA-REI.B.4B

5.

FLASHCARD QUESTION

Front

How do you solve a quadratic equation by completing the square?

Back

To solve by completing the square, rearrange the equation to isolate the constant, then add the square of half the coefficient of \( x \) to both sides, and factor the left side.

Tags

CCSS.HSA-REI.B.4B

6.

FLASHCARD QUESTION

Front

What is the standard form of a quadratic equation?

Back

The standard form of a quadratic equation is \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are constants and \( a \neq 0 \).

7.

FLASHCARD QUESTION

Front

How do you solve \( (x + 11)^2 = 36 \)?

Back

To solve, take the square root of both sides: \( x + 11 = \pm 6 \). This gives two equations: \( x + 11 = 6 \) and \( x + 11 = -6 \), leading to \( x = -5 \) or \( x = -17 \).

Tags

CCSS.HSA-REI.B.4B

Create a free account and access millions of resources

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Classlink

Continue with Classlink

Clever

Continue with Clever

or continue with

Microsoft

Microsoft

Apple

Apple

Others

Others

By signing up, you agree to our Terms of Service & Privacy Policy

Already have an account?