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Flashcard
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Chemistry
•
University
•
Practice Problem
•
Hard
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14 questions
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1.
FLASHCARD QUESTION
Front
What is a dsp3 hybrid orbital?
Back
A dsp3 hybrid orbital is formed by the combination of one d orbital, one s orbital, and three p orbitals, resulting in five equivalent orbitals. It is typically found in compounds with trigonal bipyramidal geometry, such as PCl5.
2.
FLASHCARD QUESTION
Front
Which compound is a radical?
Back
NO2 is a radical because it has an unpaired electron, making it highly reactive.
3.
FLASHCARD QUESTION
Front
How many sigma (σ) and pi (π) bonds are in carbon dioxide (CO2)?
Back
Carbon dioxide (CO2) has 2 sigma (σ) bonds and 2 pi (π) bonds.
4.
FLASHCARD QUESTION
Front
What is valence bond theory?
Back
Valence bond theory explains how atoms in a molecule bond by overlapping their atomic orbitals to form covalent bonds.
5.
FLASHCARD QUESTION
Front
What is the hybridization of methane (CH4)?
Back
Methane (CH4) has sp3 hybridization, where one s orbital and three p orbitals combine to form four equivalent sp3 hybrid orbitals.
6.
FLASHCARD QUESTION
Front
What is the geometry of a molecule with dsp3 hybridization?
Back
The geometry of a molecule with dsp3 hybridization is trigonal bipyramidal.
7.
FLASHCARD QUESTION
Front
What is the incorrect statement about valence bond theory?
Back
A dsp4 hybrid orbital does not exist; the correct term is dsp3, which allows for the formation of hypervalent compounds.
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