Special Cases for Equations

Front

Solve: 4x + 1 = 8x − 3

Back

x = 1

Front

Solve: 10x + 3 + 3x = 5x + 1 + 8x + 2

Back

infinitely many solutions

Front

Solve: 9x + 7 − 5x = 4x − 7

Back

no solutions

Front

Solve: 5x + 4 = 5x − 3

Back

no solutions

Front

What does it mean when an equation has one solution?

Back

only ONE solution will make the equation true

Front

What does it mean when an equation has no solutions?

Back

the equation will NEVER be true when any value is substituted in for the variable

Front

What does it mean when an equation has infinitely many solutions?

Back

the equation is always TRUE when any value is substituted in for the variable

Front

Identify the solution: 2x + 3 = 2x + 5

Back

no solutions

Front

Identify the solution: 3x - 4 = 2x + 1

Back

x = 5

Front

Identify the solution: 7x + 2 = 7x + 2

Back

infinitely many solutions