Grok Module 7 Practice
Flashcard
•
Computers
•
7th - 8th Grade
•
Practice Problem
•
Hard
Wayground Content
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10 questions
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1.
FLASHCARD QUESTION
Front
What one of these is a Float? True, 25, "10.8", 10.0
Back
10.0
Answer explanation
10.8 looks like a float but it is a string since it has double quotes around the number. The correct answer is 10.0
2.
FLASHCARD QUESTION
Front
Given the following: message = "I can learn hard things" Which index value will return the letter "e"?
Back
message[7]
Answer explanation
The index starts at zero and you include the spaces in the count. Therefore, "e" is located at index 7.
3.
FLASHCARD QUESTION
Front
Given the following:
message = "I can learn hard things"
What index will return the last letter in a message?
Back
message[-1]
Answer explanation
When you use a negative index it starts at the end of the message. So to access the last letter you back up one time and use message[-1]
4.
FLASHCARD QUESTION
Front
Given the following:
message = "I can learn hard things"
What index value is the same as message[-1]?
Back
message[len(message) - 1]
Answer explanation
The letter "s" is located at index 22. Don't forget the index starts at 0.
message[len(message) - 1] is the same as message[-1]. They both will access the last letter in the message.
The len(message) is 23. Therefore is you subtract one you get index 22.
5.
FLASHCARD QUESTION
Front
What letter is in name[4] for Ms. Allie Parham?
Back
A
Answer explanation
The index starts at 0 and you must count the symbols (the period) and the spaces. The correct answer when you do it this way is "A"
6.
FLASHCARD QUESTION
Front
How do you represent 15 in binary?
Back
1111
Answer explanation
Using column values. Add up each column that contains a 1. For example
8 4 2 1
1 0 1 0
This would give you 8+2 = 10 so the binary representation for 10 is 1010. Therefore to represent 15 you would need binary 1111 which gives you 8+4+2+1 = 15
7.
FLASHCARD QUESTION
Front
What is the decimal value for the binary number 1101?
Back
13
Answer explanation
To calculate the decimal value for the binary number 1101, use the column values
8 4 2 1
----------
1 1 0 1
You add the columns with a one:
8+4+1 = 13
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