Rotational Motion

Front

What is angular acceleration?

Back

Angular acceleration is the rate of change of angular velocity over time, typically measured in radians per second squared (rad/s²).

Front

What is the formula for calculating torque?

Back

Torque (τ) is calculated using the formula τ = r × F, where r is the distance from the pivot point to the point of force application, and F is the force applied.

Front

What is rotational inertia?

Back

Rotational inertia, or moment of inertia, is a measure of an object's resistance to changes in its rotational motion, depending on the mass distribution relative to the axis of rotation.

Front

What is the relationship between torque and angular acceleration?

Back

The relationship is given by Newton's second law for rotation: τ = I × α, where τ is torque, I is rotational inertia, and α is angular acceleration.

Front

What is the difference between angular speed and tangential speed?

Back

Angular speed is the rate of rotation (in radians per second), while tangential speed is the linear speed of a point on the rotating object, calculated as v = r × ω, where r is the radius and ω is angular speed.

Front

What happens to the angular speed of points on a rigid object rotating about a fixed axis?

Back

All points on a rigid object rotating about a fixed axis have the same angular speed.

Front

How do you calculate the tangential acceleration of a rotating object?

Back

Tangential acceleration (a_t) can be calculated using the formula a_t = r × α, where r is the radius and α is the angular acceleration.

Front

What is the significance of the radius in rotational motion?

Back

The radius affects both the tangential speed and the torque; larger radii result in greater tangential speeds and torques for the same force.

Front

What is the unit of torque?

Back

The unit of torque is the Newton-meter (N·m).

Front

How does the position of an object on a rotating system affect its linear speed?

Back

An object further from the center of rotation (like a horse on the outside of a merry-go-round) has a greater linear speed than one closer to the center.