A2 Midterm Review #3
Flashcard
•
Mathematics
•
11th Grade
•
Practice Problem
•
Hard
Standards-aligned
Wayground Content
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15 questions
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1.
FLASHCARD QUESTION
Front
Find the vertex of the quadratic function: f(x) = -x^2 - 4x + 12.
Back
The vertex can be found using the formula: x = -b/(2a). Here, a = -1 and b = -4. Thus, x = -(-4)/(2*-1) = -2. To find the y-coordinate, substitute x back into the function: f(-2) = -(-2)^2 - 4(-2) + 12 = 16. Therefore, the vertex is (-2, 16).
2.
FLASHCARD QUESTION
Front
What is the vertex for the function: f(x) = 4(x-2)^2 + 3?
Back
The vertex form of a quadratic function is f(x) = a(x-h)^2 + k, where (h, k) is the vertex. Here, h = 2 and k = 3, so the vertex is (2, 3).
3.
FLASHCARD QUESTION
Front
Describe the end behavior of the graph of a quadratic function.
Back
For a quadratic function in the form f(x) = ax^2 + bx + c: If a > 0, as x → ∞, y → ∞ and as x → -∞, y → ∞. If a < 0, as x → ∞, y → -∞ and as x → -∞, y → -∞.
Tags
CCSS.HSF-IF.C.7A
4.
FLASHCARD QUESTION
Front
The parabola y = -2x^2 - 4x + 1 will open in which direction?
Back
The parabola opens downwards because the coefficient of x^2 (which is -2) is negative.
Tags
CCSS.HSF-IF.C.7A
5.
FLASHCARD QUESTION
Front
What is the standard form of a quadratic function?
Back
The standard form of a quadratic function is f(x) = ax^2 + bx + c, where a, b, and c are constants and a ≠ 0.
6.
FLASHCARD QUESTION
Front
How do you find the axis of symmetry for a quadratic function?
Back
The axis of symmetry can be found using the formula: x = -b/(2a), where a and b are the coefficients from the standard form of the quadratic function.
7.
FLASHCARD QUESTION
Front
What is the significance of the vertex in a parabola?
Back
The vertex represents the highest or lowest point of the parabola, depending on whether it opens upwards or downwards.
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