Derivative Quotient Rule

Derivative Quotient Rule

Assessment

Flashcard

Mathematics

12th Grade

Practice Problem

Hard

Created by

Wayground Content

FREE Resource

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15 questions

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1.

FLASHCARD QUESTION

Front

What is the Quotient Rule in calculus?

Back

The Quotient Rule states that if you have a function that is the quotient of two functions, say \( f(x) = \frac{g(x)}{h(x)} \), then the derivative is given by \( f'(x) = \frac{g'(x)h(x) - g(x)h'(x)}{(h(x))^2} \).

2.

FLASHCARD QUESTION

Front

Differentiate the function \( y = \frac{x^2 + 6}{2x - 7} \).

Back

Using the Quotient Rule, \( y' = \frac{(2x)(2x - 7) - (x^2 + 6)(2)}{(2x - 7)^2} = \frac{2x^2 - 14x - 12}{(2x - 7)^2} \).

3.

FLASHCARD QUESTION

Front

Find the derivative of \( f(x) = \frac{2x - 7}{x + 3} \).

Back

Using the Quotient Rule, \( f'(x) = \frac{(2)(x + 3) - (2x - 7)(1)}{(x + 3)^2} = \frac{13}{(x + 3)^2} \).

4.

FLASHCARD QUESTION

Front

What is the first step in applying the Quotient Rule?

Back

Identify the numerator and denominator functions, \( g(x) \) and \( h(x) \), respectively, in the quotient \( f(x) = \frac{g(x)}{h(x)} \).

5.

FLASHCARD QUESTION

Front

Differentiate \( y = \frac{2}{2x^4 - 5} \).

Back

Using the Quotient Rule, \( y' = \frac{0(2x^4 - 5) - 2(8x^3)}{(2x^4 - 5)^2} = \frac{-16x^3}{(2x^4 - 5)^2} \).

6.

FLASHCARD QUESTION

Front

What is the derivative of a constant?

Back

The derivative of a constant is zero. For example, if \( c \) is a constant, then \( \frac{d}{dx}(c) = 0 \).

7.

FLASHCARD QUESTION

Front

Differentiate \( y = \frac{x^2}{3x - 1} \).

Back

Using the Quotient Rule, \( y' = \frac{(2x)(3x - 1) - (x^2)(3)}{(3x - 1)^2} = \frac{3x^2 - 2x}{(3x - 1)^2} \).

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