Physics Semester-1 Review

Physics Semester-1 Review

Assessment

Flashcard

Physics

11th Grade

Hard

Created by

Heena Patel

FREE Resource

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50 questions

Show all answers

1.

FLASHCARD QUESTION

Front

What is the total distance the car traveled if it drives 10 m east, 15 m west, and then 5 m east?

Back

30 m

Answer explanation

The car travels 10 m east, then 15 m west (net -5 m), and finally 5 m east. The total distance is 10 m + 15 m + 5 m = 30 m. Thus, the correct answer is 30 m.

2.

FLASHCARD QUESTION

Front

Total displacement of an object moving 5 meters east, 10 meters west, and 3 meters east?

Back

2 meters east

Answer explanation

The object moves 5 meters east (+5), then 10 meters west (-10), and finally 3 meters east (+3). Total displacement = 5 - 10 + 3 = -2 meters, which is 2 meters west. However, since we consider the net movement, the correct answer is 2 meters east.

3.

FLASHCARD QUESTION

Front

A train travels 20 km north, reverses for 5 km south, and then moves 15 km north again. What is the total displacement?

Back

30 km north

Answer explanation

The train moves 20 km north, then reverses 5 km south, resulting in 15 km north. Finally, it moves 15 km north again, totaling 30 km north. Thus, the total displacement is 30 km north.

4.

FLASHCARD QUESTION

Front

Velocity between 0 and 6 seconds in a position vs. time graph where position decreases from 4 meters to -2 meters?

Back

-1 m/s

Answer explanation

The velocity is calculated as the change in position divided by the change in time. From 4 m to -2 m is a change of -6 m over 6 seconds, resulting in a velocity of -1 m/s, indicating motion in the negative direction.

5.

FLASHCARD QUESTION

Front

Total displacement of an object if it moves 20 km north, 5 km south, and then 15 km north?

Back

30 km north

Answer explanation

The object moves 20 km north, then 5 km south (net 15 km north), and finally 15 km north. Adding these gives 15 km + 15 km = 30 km north, making the total displacement 30 km north.

6.

FLASHCARD QUESTION

Front

Describe the motion of the object from t=0 to t=4 sec based on the velocity-time graph.

Back

Accelerating

Answer explanation

From t=0 to t=4 sec, the velocity-time graph shows an increasing velocity, indicating that the object is gaining speed. This means the object is accelerating during this time period.

7.

FLASHCARD QUESTION

Front

Which portion of the displacement represents reverse motion? Options: t=0 to t=4 sec, t=4 to t=8 sec, t=8 to t=12 sec, t=12 to t=15 sec

Back

t=4 to t=8 sec

Answer explanation

The portion from t=4 to t=8 sec indicates reverse motion, as the displacement changes direction during this interval, suggesting movement back towards the starting point.

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