2nd Period Quadratic area problems

2nd Period Quadratic area problems

Assessment

Flashcard

Mathematics

9th Grade

Practice Problem

Hard

CCSS
3.MD.C.7B, 6.EE.C.9, 6.EE.B.6

+4

Standards-aligned

Created by

Wayground Content

FREE Resource

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15 questions

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1.

FLASHCARD QUESTION

Front

What is the formula for the area of a rectangle?

Back

Area = Length × Width

Tags

CCSS.3.MD.C.7B

CCSS.4.MD.A.3

2.

FLASHCARD QUESTION

Front

If the width of a rectangle is 5 times the length, how can we express the area?

Back

Area = Length × (5 × Length) = 5 × Length²

Tags

CCSS.6.EE.B.6

3.

FLASHCARD QUESTION

Front

What does it mean if the width of a rectangle is described as '8 meters less than its length'?

Back

Width = Length - 8

Tags

CCSS.6.EE.C.9

4.

FLASHCARD QUESTION

Front

How do you set up an equation for a rectangle's area if the area is given as 84 m² and the width is 8 meters less than the length?

Back

x(x - 8) = 84, where x is the length.

5.

FLASHCARD QUESTION

Front

What is the relationship between the length and width if the length is 6 meters more than the width?

Back

Length = Width + 6

Tags

CCSS.6.EE.C.9

6.

FLASHCARD QUESTION

Front

How do you find the dimensions of a rectangle if the area is given and a relationship between length and width is provided?

Back

Set up an equation using the area formula and the relationship, then solve for the unknowns.

7.

FLASHCARD QUESTION

Front

If a rectangle has an area of 24 square units and the width is 5 units less than the length, what is the equation to find the length?

Back

Length × (Length - 5) = 24

Tags

CCSS.HSA.CED.A.1

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