Order of Operations Review

Front

What is the Order of Operations?

Back

The Order of Operations is a set of rules that determines the sequence in which calculations are performed in a mathematical expression. The acronym PEMDAS helps remember the order: Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right).

Tags

CCSS.7.NS.A.3

Front

What does PEMDAS stand for?

Back

PEMDAS stands for Parentheses, Exponents, Multiplication, Division, Addition, and Subtraction. It is the order in which operations should be performed.

Tags

CCSS.7.EE.B.3

Front

What is the first step in the Order of Operations?

Back

The first step is to solve expressions inside Parentheses.

Tags

CCSS.6.EE.A.2C

Front

How do you handle Exponents in the Order of Operations?

Back

Exponents are calculated after parentheses but before multiplication, division, addition, and subtraction.

Tags

CCSS.6.EE.A.1

Front

What is the result of 3 + 4 × 2?

Back

The result is 11. According to the Order of Operations, you multiply first (4 × 2 = 8) and then add (3 + 8 = 11).

Tags

CCSS.5.OA.A.1

CCSS.5.OA.A.2

Front

What is the result of (5 + 3) × 2?

Back

The result is 16. First, solve the parentheses (5 + 3 = 8), then multiply by 2 (8 × 2 = 16).

Tags

CCSS.5.OA.A.1

CCSS.5.OA.A.2

Front

What is the result of 10 - 2 × 3?

Back

The result is 4. According to the Order of Operations, you multiply first (2 × 3 = 6) and then subtract (10 - 6 = 4).

Tags

CCSS.5.OA.A.1

CCSS.5.OA.A.2

Front

What is the result of 8 ÷ 4 + 2?

Back

The result is 4. According to the Order of Operations, you divide first (8 ÷ 4 = 2) and then add (2 + 2 = 4).

Tags

CCSS.5.OA.A.1

CCSS.5.OA.A.2

Front

What is the result of 2 + (3 × 4) - 5?

Back

The result is 9. First, solve the parentheses (3 × 4 = 12), then add and subtract (2 + 12 - 5 = 9).

Tags

CCSS.5.OA.A.1

CCSS.5.OA.A.2

Front

What is the result of 6 + 2 × (3 - 1)?

Back

The result is 10. First, solve the parentheses (3 - 1 = 2), then multiply (2 × 2 = 4), and finally add (6 + 4 = 10).

Tags

CCSS.5.OA.A.1

CCSS.5.OA.A.2