Probability Tree Diagrams & Relative Frequency

Probability Tree Diagrams & Relative Frequency

Assessment

Flashcard

Mathematics

11th Grade

Practice Problem

Hard

CCSS
7.SP.C.5, 7.SP.C.6, 7.SP.C.8B

+3

Standards-aligned

Created by

Wayground Content

FREE Resource

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15 questions

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1.

FLASHCARD QUESTION

Front

What is a probability tree diagram?

Back

A probability tree diagram is a graphical representation that shows all possible outcomes of a probability experiment, illustrating the paths leading to each outcome.

Tags

CCSS.7.SP.C.8B

2.

FLASHCARD QUESTION

Front

How do you calculate the total number of outcomes in a probability tree diagram?

Back

Multiply the number of outcomes at each stage of the experiment. For example, rolling a die (6 outcomes) and flipping a coin (2 outcomes) results in 6 * 2 = 12 total outcomes.

Tags

CCSS.7.SP.C.8B

3.

FLASHCARD QUESTION

Front

What is relative frequency?

Back

Relative frequency is the ratio of the number of times an event occurs to the total number of trials or observations, often expressed as a fraction or percentage.

Tags

CCSS.7.SP.C.6

4.

FLASHCARD QUESTION

Front

How do you calculate relative frequency?

Back

Relative frequency = \( \frac{\text{Number of successful outcomes}}{\text{Total number of trials}} \)

Tags

CCSS.7.SP.C.6

5.

FLASHCARD QUESTION

Front

If a coin is flipped 30 times and lands on tails 20 times, what is the relative frequency of tails?

Back

Relative frequency of tails = \( \frac{20}{30} = \frac{2}{3} \) or approximately 0.67.

Tags

CCSS.7.SP.C.6

6.

FLASHCARD QUESTION

Front

What is the probability of drawing two red counters from a bag with replacement?

Back

If there is 1 red counter in a bag of 8, the probability of drawing two red counters with replacement is \( \left(\frac{1}{8}\right) \times \left(\frac{1}{8}\right) = \frac{1}{64} \).

7.

FLASHCARD QUESTION

Front

What is the probability of drawing two red counters from a bag without replacement?

Back

If there are 3 red counters in a bag of 10, the probability of drawing two red counters without replacement is \( \frac{3}{10} \times \frac{2}{9} = \frac{6}{90} \).

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