Civilwar-Day 18-Oct 14-PWD-Water demand& population forecasting
Flashcard
•
Professional Development
•
1st - 5th Grade
•
Practice Problem
•
Hard
WINCENTRE CLASSES
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10 questions
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1.
FLASHCARD QUESTION
Front
Compute the 'fire demand' for a city of 2 lac population by Freeman's formula.
Back
81.792 MLD
Answer explanation
Freeman’s formula: Q = 1136 × P⁰·⁵. For P = 2 lac (0.2 million), Q = 1136 × √0.2 ≈ 508. MLD = 49.07.
2.
FLASHCARD QUESTION
Front
How much percentage of total water consumption is lost in theft and waste?
Back
15
Answer explanation
Water loss in distribution systems due to leakage, theft, and wastage is typically around 15% of total consumption.
3.
FLASHCARD QUESTION
Front
What are distribution mains designed for?
Back
Maximum hourly demand of maximum day
Answer explanation
Distribution mains must handle the highest expected flow — the maximum hourly demand on the maximum day.
4.
FLASHCARD QUESTION
Front
Population is 1,00,000. The average water consumption is 200 lpcd. The capacity of distribution system is (Take fire demand 61 MLD).
Back
81 MLD
Answer explanation
Average demand = 1,00,000 × 200 / 1,000,000 = 20 MLD. Adding fire demand (61 MLD) gives total =81MLD
5.
FLASHCARD QUESTION
Front
If the average daily water consumption of a city is 24,000,000 liters per day, what is the peak hourly demand?
Back
1800 cu m/hr
Answer explanation
Given:
Average daily consumption = 24,000,000 L/day = 24,000 m³/day
Step 1:
Average hourly demand = 24,000 / 24 = 1,000 m³/hr
Step 2:
Peak hourly demand ≈ 1.8 × average hourly demand
= 1.8 × 1,000 = 1,800 m³/hr
✅ Answer: Peak hourly demand = 1,800 m³/hr
6.
FLASHCARD QUESTION
Front
The average consumption of water required in factories in lpcd is .....................
Back
30–45
Answer explanation
Industrial or factory water consumption typically ranges from 30 to 45 liters per capita per day (lpcd).
7.
FLASHCARD QUESTION
Front
The population of a city in the first three consecutive years is given as 6000, 8000, and 10000 respectively. What is the population of the city in the fourth continuous year, according to the geometric increase method?
Back
12900
Answer explanation
Geometric increase method: Growth rate = (10000/6000)^(1/2) – 1 = 0.29. Population in 4th year = 10000 × (1 + 0.29) =12900
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