Tes Diagnostik Kelas 7

10 jam -> 4 kemeja

x jam -> 12 kemeja

(perbandingan senilai)

$$\frac{10}{x}=\frac{4}{12}$$

$$x=\frac{10\times12}{4}$$

$$x=30$$ jam

40 anak -> 30 hari

60 anak -> x hari

(perbandingan berbalik nilai)

$$\frac{40}{60}=\frac{x}{30}$$

$$x=\frac{40\times30}{60}$$

$$x=20$$ hari

$$\frac{3}{4}\ jam\ =\ \frac{3}{4}\times60\ menit\ =\ 45\ menit$$

$$Suhu\ freezer\ =\ -17+3\left(\frac{45}{5}\right)$$

$$Suhu\ freezer\ =\ -17+3\left(9\right)$$

$$Suhu\ freezer\ =\ -17+27$$

$$Suhu\ freezer\ =\ 10\degree C$$

$$4\frac{2}{3}-1\frac{1}{2}\div2\frac{1}{4}=\frac{14}{3}-\frac{3}{2}\div\frac{9}{4}$$

$$=\frac{14}{3}-\frac{3}{2}\times\frac{4}{9}$$

$$=\frac{14}{3}-\frac{2}{3}$$

$$=\frac{12}{3}$$

$$=4$$

$$0,125=\frac{125}{1000}\ \left(\frac{\div25}{\div25}\right)$$

$$=\frac{5}{40}\ \left(\frac{\div5}{\div5}\right)$$

$$=\frac{1}{8}$$

-5

$$3\left(2x-4y\right)-5\left(2x+3y\right)=6x-12y-10x-15y$$

$$=-4x-27y$$

$$\left(3x+2\right)\left(3x-2\right)=9x^2-6x+6x-4$$

$$=9x^2-4$$

$$L=\left(2x+3\right)^2$$

$$L=4x^2+12x+9$$

Diketahui=

$$p=3l$$

$$K=96\ cm$$

Ditanya= luas?

Jawab=

$$2\left(p+l\right)=96$$

$$p+l=48$$

$$3l+l=48$$

$$4l=48$$

$$l=12\ cm$$

$$p=3\left(12\right)=36\ cm$$

$$L=36\times12$$

$$L=432\ cm^2$$