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Literal Equations

Literal Equations

Assessment

Presentation

Mathematics

9th - 10th Grade

Medium

CCSS
HSA.CED.A.4, 6.EE.B.7, HSA.REI.B.3

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11 Slides • 6 Questions

1

Literal Equations

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2

Literal Equations

Equations that contain two or more variables. In this lesson we will learn to rearrange formulas.

3

A. How can we solve :

 4x  =  164x\ \ =\ \ 16  

4

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5

What is the reason for dividing?

  •  4x4x  is multiplication

  • The inverse of multiplication is division.

  • So to undo multiplication we divide.

  • So by rearranging we isolated the variable and "x" was found

6

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 A = l × wA\ =\ l\ \times\ w  

  • The operation is multiplication

  • The inverse is division

  •  w = Alw\ =\ \frac{A}{l}  

8

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 V = l x w x hV\ =\ l\ x\ w\ x\ h  

  • The operation is multiplication

  • The inverse is division

  •  h = Vl x wh\ =\ \frac{V}{l\ x\ w}  

10

Multiple Choice


 B = a + cB\ =\ a\ +\ c  

Solve for "a". What is the inverse operation to be used to undo the equation?

1

addition

2

multiplication

3

subtraction

4

division

11

Multiple Choice

  D = rt\ D\ =\ rt  

Solve for "t"

1

 t= Drt=\ \frac{D}{r}  

2

 t= D  rt=\ D\ -\ r   t= tDt=\ \frac{t}{D}  

3

 t= D+ rt=\ D+\ r  

12

Formulas with more than one operation

  •  y = mx + b ; solve for "x"y\ =\ mx\ +\ b\ ;\ solve\ for\ "x"  

  • What are the operations in the formula?

  • multiplication and addition

  • What are the inverse operations?

  • division and subtraction

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 y = mx + b ; solve for "x"y\ =\ mx\ +\ b\ ;\ solve\ for\ "x"  

  • 1st subtract "b"            y  b =mxy\ -\ b\ =mx  

  • 2nd divide by "m"         (y  b)m =x\frac{\left(y\ -\ b\right)}{m}\ =x  

14

Multiple Choice

 y= mx +b; solve for "m"  y=\ mx\ +b;\ solve\ for\ "m"\ \   

What is the first step?

1

add

2

subtract

3

multiplication

4

division

15

Multiple Choice

 y = mx + b; solve for by\ =\ mx\ +\ b;\ solve\ for\ b  

1

 ymx = by-mx\ =\ b  

2

 y+mx = by+mx\ =\ b  

3

 ymx = b\frac{y}{mx\ }=\ b  

4

 y + mx = by\ +\ mx\ =\ -b  

16

Multiple Choice

 5x y = 165x\ -y\ =\ 16 solve for "y" 

1

 y =16 + 5x-y\ =16\ +\ 5x  

2

 y=5x + 16y=-5x\ +\ 16  

3

 y = 165xy\ =\ \frac{16}{5x}  

4

 y=5x16y=\frac{5x}{16}  

17

Poll

What is your comfort level of rearranging formulas (literal equations)?

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Literal Equations

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