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Evaluating Functions - Algebra

Evaluating Functions - Algebra

Assessment

Presentation

Mathematics

9th Grade

Practice Problem

Medium

CCSS
HSF.IF.A.2, 8.F.A.1, 8.EE.C.7B

+2

Standards-aligned

Created by

Callie Keller

Used 191+ times

FREE Resource

11 Slides • 5 Questions

1

Evaluating Functions

Algebra

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Goals:

  • Determine output values given input values

  • Determine input values given output values

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Key Words

  • Evaluate: to determine the value of something

  • Function: a relation in which each element of the domain is mapped to (paired with) exactly one element of the range

  • Input: the value that is transformed by a process and becomes an output

  • Output: The result of an input that has been transformed by a process

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5

Multiple Choice

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 f(2)=?f\left(2\right)=?  

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-2

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-6

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-38

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58

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Finding an output value

  •  f(3)=?f\left(3\right)=?  

  •  f(3)=(3)43(3)3+2(3)1f\left(3\right)=\left(3\right)^4-3\left(3\right)^3+2\left(3\right)-1  

  •  f(3)=813(27)+2(3)1f\left(3\right)=81-3\left(27\right)+2\left(3\right)-1  

  •  f(3)=8181+61f\left(3\right)=81-81+6-1  

  •  f(3)=5f\left(3\right)=5  

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Multiple Choice

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 f(1.5)=?f\left(1.5\right)=?  

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0

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2

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6

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-1

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Determine the input of a function

  •  f(x)=13x2f\left(x\right)=\frac{1}{3}x-2  

  • Determine the input that would give an output value of -2/3

  •  23=13x2-\frac{2}{3}=\frac{1}{3}x-2  

  •  (63)+(23)=13x(63)+(63)\left(\frac{6}{3}\right)+\left(-\frac{2}{3}\right)=\frac{1}{3}x-\left(\frac{6}{3}\right)+\left(\frac{6}{3}\right)  

  •  43=13x\frac{4}{3}=\frac{1}{3}x  

  •  3×43=13x×33\times\frac{4}{3}=\frac{1}{3}x\times3  

  •  x=4x=4  

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Multiple Choice

 f(x)=14x+3f\left(x\right)=\frac{1}{4}x+3  Determine the input value that would give an output value of  144\frac{14}{4}  .

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0

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1

3

2

4

3

13

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Poll

Rate your level of understanding

5- I've got this

4 - I am getting the hang of it

3 - Practice will help me fully understand

2- I have some questions

1 - I am lost

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16

Multiple Choice

 f(x)=13x+2f\left(x\right)=\frac{1}{3}x+2  

What is the inverse of the equation above?

1

 h(x)=13x2h\left(x\right)=\frac{1}{3}x-2  

2

 h(x)=13x+2h\left(x\right)=\frac{1}{3}x+2  

3

 h(x)=3x2h\left(x\right)=3x-2  

4

 h(x)=3x6h\left(x\right)=3x-6  

Evaluating Functions

Algebra

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