October 15th Independent Work

​Independent Work

Area, perimeter, and multiplication review​

Perimeter= L+L+W+W

The perimeter of this rectangle is 7+7+3+3=20

Area= LXW

The area of this rectangle is 7x3=21 and would be reported in squared units.

Multiple Choice

What is the perimeter of a rectangle with a width of 4 in and a length of 7 in?

• 28 in

• 22in

Multiple Choice

What is the area of a rectangle with a width of 4 in and a length of 7 in?

• 28 in²

• 22 in

Open Ended

If you have a square with a length of 5m, what is the width? Explain.

Open Ended

If you have a square with an area of 36ft, what is the length of the square? Explain your thinking.

Multiple Choice

50x6=

• 30

• 300

• 3,000

Multiple Choice

435 x 5=

• 2,175

• 2,055

• 2,165

• 2,000