

divizibilitate
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Mathematics
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3rd Grade
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Hard
petru scuturici
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divizibilitate

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Divizibilitate
27:3=9 spunem ca 3/27 pentru ca exista 9X3=27
25 nu este divzibil cu 4 deoarece restul impartiri lui 25:4=6 r1
Def.Spunem ca un nr.natural a este divizibil cu un numar natural b daca exista un numar natural c,astfel incat
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Descompunerea numerlelor in factori primi
6=2⋅3Def.Un numar care are exact 2 divizori pe 1 si pe el insasi se numeste numar prim.
Numere prime :2;3;5;7;11;13;17;19;23............
Orice numar natural poate fi scris ca produs de puteri de numere prime.
ex
4
Aflarea c.m.m.d.c si c.m.m.m.c
Cum calculam c.m.m.m.c a doua sau mai multe numere natuarale:
-descompunem numerele in produs de factori priimi;
-c.m.m.d.c este produsul factorilorm primi comuni ,luati o singura data ,la puterea cea mai mica
Not (a.b) cel mai mare divizor comun
Ex:(6,10)=2,deoarece 2/6 si 2/10 si este cel mai mic mdivizor cu aceasta prorietate
(20,24)=22=4 ,deoarece 4/20 si 4/24
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Aflarea c.m.m.m.c a doua sau mai multe numere naturale
⌈a,b⌉=cel mai mic multiplu comun a numerelor a si b ⌈a,b⌉=cel mai mic multiplu comun al numerelor a si b
Aflarea c.m.m.m.c a doua sau mai multe numere naturale
-descompunem numerele in produse de puteri de factori primi;
-c.m.m.m.c este produsul factorilor primi comuni si necomuni ,luati o singura data,la puterea cea mai mare
Not. ⌈a,b⌉=cel mai maic multiplu comun al numerelor a si b ex: ⌊6,10⌋=2⋅3⋅5=30
6=2⋅3;10=2⋅5
⌈12,60⌉=22⋅3⋅5=60, deoarece 12=22⋅3 .iar 60=22⋅3⋅5
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Aplicatii
(a)⌈40,60⌉=....;b⌈18,36⌉=.........;c⌈150,100⌉=......
1.Aflatic.m.m.md.c al urmatoarelor perechi de numere:
a)(11,33)=............2:..b) (40,60)=....;c)(36,42)=.......
2.Aflati c.m.m.m.c al urmatoarelor perechi de numere:
divizibilitate

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