Practice for Creating Center Form Equations

Practice for Creating Center Form Equations

Multiple Choice

Which is the equation for

3x² - y² + 12x - 8y - 16 = 0

in center form

• $\frac{\left(x\ +2\right)^2}{4}-\frac{\left(y\ +4\right)^2}{12}\ =\ 1$

• $\frac{\left(x\ +2\right)^2}{4}-\frac{\left(y\ -4\right)^2}{12}\ =\ 1$

• $\frac{\left(x\ +6\right)^2}{23}-\frac{\left(y\ +4\right)^2}{69}\ =\ 1$

• $\frac{\left(x\ +6\right)^2}{18}-\frac{\left(y\ -4\right)^2}{36}\ =\ 1$

3x² - y² + 12x - 8y - 16 = 0

How'd you get there?

Multiple Choice

Which is the equation for

2x² + 3y² + 8x + 24y + 2 = 0

in center form

•  $\frac{\left(x\ +2\right)^2}{54}+\frac{\left(y\ +4\right)^2}{54}\ =\ 1$ 

•  $\frac{\left(x\ +2\right)^2}{27}+\frac{\left(y\ +4\right)^2}{18}\ =\ 1$ 

•  $\frac{\left(x\ +4\right)^2}{79}+\frac{\left(y\ +12\right)^2}{\frac{158}{3}}\ =\ 1$ 

•  $\frac{\left(x\ +4\right)^2}{27}+\frac{\left(y\ +12\right)^2}{18}\ =\ 1$ 

2x² + 3y² + 8x + 24y + 2 = 0

How'd you get there?

Multiple Choice

Which is the equation for

 $2x-3y^2+6y-5=0$  in vertex form.

•  $x\ =\ 3\left(y-1\right)^2+1$ 

•  $x\ =\ 3\left(y-1\right)^2+2$ 

•  $x\ =\ \frac{3}{2}\left(y-1\right)^2+1$ 

•  $x\ =\ \left(3y-3\right)^2-4$ 

2x-3y²+6y-5=0

How'd you get there?

Poll

How are you doing?

1-Aweful

5-Awesome

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