

chapter 9: Application of Differentiation
Presentation
•
Mathematics
•
12th Grade - University
•
Medium
+1
Standards-aligned
Aziana Musa
Used 9+ times
FREE Resource
11 Slides • 9 Questions
1
Chapter 9: Application of Differentiation
9.1 Tangent and Normal
9.2 Extremum Problem
9.3 Application of Differentiation in Economics and business

2
9.1 Tangent and Normal Equation
MT=f′(x)=dxdy
MN=−MT1
Equation y−y1=m(x−x1)
3
9.2 Extremum problems
f′(x)=dxdy=0 to find stationary point(s)
2 method to find the nature of stationary points ( first derivative and second derivative)
4
Method 1 (First Derivative)
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6
Method 2 (2nd Derivative/ f''(x))
f′′(x)>0 minimum point
f′′(x)<0 maximum point
f′′(x)=0 (test failed ) back to first derivative test)
7
Method 2 (second derivative)
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9
9.3 Application of Differentiation in Economics and business
C(x)=xC(x) (Average Cost)
R(x)=p(x).x
π(x)=R(x)−C(x)
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11
12
Multiple Choice
Write the equation of the normal line of: f(x)=2x2−x1 at x = 1
y=−51x+54
y=5x−6
y−1=5(x−1)
y−1=−51(x−1)
13
Multiple Choice
What is the equation of the line tangent to f(x)= 4x2+2x-1 at x=0?
y+1=2(x+1)
y=2x-1
y=2x+2
y= -x-1
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Multiple Choice
Local maximum point is obtained when
f ' (x) exchange from negative to positive
f '' (x) exchange from positive to negative
f ' (x) exchange from positive to negative
f '' (x) exchange from negative to positive
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Multiple Choice
16
Multiple Choice
17
Multiple Choice
What is the stationary points for the curve f(x) = x3 +3x2 - 24x and determine their nature.
Maximum point : (2, -28) and minimum point : (-4, 80)
Minimum point : (2, 28) and maximum point : (-4, 80)
Minimum point : (2, -28) and maximum point : (4, 80)
Minimum point : (2, -28) and maximum point : (-4, 80)
18
Multiple Choice
What is the stationary point for the curve y=x2 - 4?
A minimum at ( 0, -4)
A maximum at (0, -4)
A minimum at (0,4)
A maximum at (0,4)
19
Multiple Choice
20
Multiple Choice
The revenue function for selling x kg of butter cake is given by
R(x)=30x−x2. the total cost to produce xkg of butter cake is given by the cost function C(x)=10x+20 . Find the maximum profitRM 100
RM 90
RM80
RM 120
Chapter 9: Application of Differentiation
9.1 Tangent and Normal
9.2 Extremum Problem
9.3 Application of Differentiation in Economics and business

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