Unit 2 lesson 2: fractions and adding integers

Unit 2 lesson 2: fractions and adding integers

Multiple Choice

10 + (-65)=

• 75

• -75

• 55

• -55

Multiple Choice

-5 + -42 =

• 47

• -47

• 37

• -37

Multiple Choice

-1 + -7 =

• -8

• 8

• 6

• -6

Multiple Choice

3 + - 8 =

• 11

• 5

• -5

• -11

Multiple Choice

- 8 + 11=

• 3

• -19

• -3

• 19

Multiple Choice

9 + -3 =

• 12

• - 12

• 3

• 6

How do we get the common or same denominator?

To make the same denominator we need to multiply one or both of the fractions by a number. You must multiply the top and bottom by the same number.

Example #1: copy in notebook

 $\frac{1}{6}\ +\frac{4}{15}$    First think what can I turn 6 and 15 into? Then multiply both fractions to get the same denominator
 $\frac{1\ \cdot5}{6\ \cdot5}\ \ \ \ +\ \frac{4\ \cdot2}{15\cdot2}=>\ \frac{5}{30}+\frac{8}{30}=\frac{13}{30}$  

When you have dominator all you need to do is add the numerators and keep the denominator the same and simplify if you need to only.

Multiple Choice

• 12/17
• 17/20
• 20/17
• 2  1/2

Multiple Choice

• 13/15

• 1 7/12

• 1

• 9/15

Multiple Choice

Is this a correct answer?

• Yes, the student correctly added.

• No, you cannot add unlike denominators

• No, 5 + 7 is not 12

• No, 2 + 3 is not 5

Multiple Choice

How do I add this fraction?

• 2/7
• 2/12
• 1/7
• 7/12

What if the fraction has negatives? Copy

• Follow the same steps as adding fractions

• Get the common denominator but don’t forget to put the negative sign In the numerator

• Add the numerators, keep the denominator the same

• Simplify if you need

Multiple Choice

Calculate $-\frac{3}{5\ }+\left(-\frac{1}{3}\right)$  

•  $-\frac{4}{15}$  

•  $\frac{14}{15}$  

•  $-\frac{14}{15}$  

•  $-\frac{3}{8}$  

Multiple Choice

Calculate $-\frac{2}{5}+\left(-\frac{1}{5}\right)$  

•  $-\frac{3}{5\ }$  

•  $-\frac{1}{5\ }$  

•  $\frac{1}{5\ }$  

•  $\frac{3}{5\ }$