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index notation

index notation

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Mathematics

3rd - 12th Grade

Hard

Created by

Siti Ahmad

Used 8+ times

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6 Slides • 0 Questions

1

LAW OF INDICES

by cikgu mas

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 am  × an  = am+na^{m\ \ }\times\ a^{n\ \ }=\ a^{m+n}  


EXAMPLE : 

 23 ×24 =23+4 2^{3\ }\times2^4\ =2^{3+4\ }  

 57 ×53  =57+35^7\ \times5^{3\ }\ =5^{7+3}  

 1121 ×115 =1121+511^{21}\ \times11^5\ =11^{21+5}  

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QUESTION :

Simplify each of the following .

a )  72 ×737^2\ \times7^3  


b)  (0.2)2 × (0.2)4 ×(0.2)5\left(0.2\right)^2\ \times\ \left(0.2\right)^4\ \times\left(0.2\right)^5  

c)  2k2 ×4k72k^2\ \times4k^7  

d)  3m4 ×16m8 ×12m3m^{4\ }\times\frac{1}{6}m^8\ \times12m  

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Solution :

a )  72 ×737^2\ \times7^3  


 =72 +3=7^{2\ +3}  

 =75=7^5  

b)  (0.2)2 ×(0.2 )4 ×(0.2 )5\left(0.2\right)^2\ \times\left(0.2\ \right)^4\ \times\left(0.2\ \right)^5  

 =(0.2)2+4+5=\left(0.2\right)^{2+4+5}  

 =(0.2 )11=\left(0.2\ \right)^{11}  

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c ) 2k2 ×4k72k^2\ \times4k^7  

 =(2 ×4 ) (k2 × k7)=\left(2\ \times4\ \right)\ \left(k^2\ \times\ k^7\right)  

 =8k2 +7=8k^{2\ +7}  
 =8k9=8k^9  

d )  3m4 ×16m8 ×12m3m^4\ \times\frac{1}{6}m^8\ \times12m  

 =(3×16 ×12)(m4 ×m8 ×m1)=\left(3\times\frac{1}{6}\ \times12\right)\left(m^4\ \times m^8\ \times m^1\right) 

 =6m4+8+1=6m^{4+8+1}  
 =6m13=6m^{13}  
  

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thats all...

thank you and good luck!!!!!!

LAW OF INDICES

by cikgu mas

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