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30-60-90

30-60-90

Assessment

Presentation

Mathematics

10th Grade

Practice Problem

Medium

CCSS
HSG.SRT.C.8, 8.G.B.8

Standards-aligned

Created by

Anna Cockrum

Used 75+ times

FREE Resource

7 Slides • 5 Questions

1

30-60-90

February 4, 2021

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2

Multiple Choice

When finding the diagonal of any

 45°45\degree  right triangle, you always do what?

1

multiply the sides by  2\sqrt{2}  

2

divide the sides by  2\sqrt{2}  

3

Multiple Choice

When finding the side of any

 45°45\degree   right triangle, you always 

1

multiply the diagonal by  2\sqrt{2}  

2

divide the diagonal by  2\sqrt{2}  

4

30 - 60 - 90 right triangles

These numbers refer to the angle measures of a right triangle

5

Evaluating a 30-60-90 triangle

  • The short leg is always between the 60 and 90. This leg is always the one we use to measure.

  • The long leg is always 

     3\sqrt{3}   times longer than the short leg

  • The hypotenuse (diagonal) is always twice the short leg

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6

Multiple Choice

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Given that 5 is the short leg, what is the length of the long leg, b?

1

535\sqrt{3}

2

15\sqrt{15}

3

353\sqrt{5}

4

not enough information

7

b =  535\sqrt{3}  

To find the long leg: take the length of the short leg and multiply it by  3\sqrt{3}  

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8

Multiple Choice

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Given that 5 is the short leg, what is the length of the hypotenuse, c?

1

10

2

 10\sqrt{10} 

3

 525\sqrt{2} 

4

not enough information

9

c = 10

To find the hypotenuse, take the length of the short side and double it.

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10

Find n and m

  • Since 12 is the hypotenuse, we know that 12 = 2n (because the hypotenuse is always 2 times the short leg

  • Know that 12 = 2n

  • divide by 2

  • n = 6

  •  m=n3m=n\sqrt{3}  

  •  m=63m=6\sqrt{3}  

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11

Open Ended

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Find y and x

12

Find x and y

  •  y=442=22y=\frac{44}{2}=22  

  •  x=y3=223x=y\sqrt{3}=22\sqrt{3}  

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30-60-90

February 4, 2021

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