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Staying in Balance! (1-Step)

Staying in Balance! (1-Step)

Assessment

Presentation

Mathematics

6th Grade

Medium

CCSS
6.EE.B.7, HSA.CED.A.3, 7.NS.A.1C

+3

Standards-aligned

Created by

Mary Luksetich

Used 9+ times

FREE Resource

5 Slides • 18 Questions

1

Staying in Balance!

I can add or remove objects from each side of a hanger to keep the hanger balanced.


I can represent a hanger diagram with an equation.

Slide image

2

Multiple Choice

A symbol for an unknown value is called a _______________. It is usually a letter such as a, X or Y.

1

Constant

2

Coefficient

3

Solution

4

Variable

3

Multiple Choice

The number directly in front of the variable is called the _______?

1

Variable

2

Coefficient

3

Equation

4

Solution

4

Multiple Choice

The number that can replace the variable and make the equation TRUE.

1

Coefficient

2

Variable

3

Solution

4

Equation

5

Multiple Choice

A math statement saying two expressions are equal (contains an equal sign!).

1

Coefficient

2

Variaable

3

Solution

4

Equation

6

Multiple Choice

What is the variable in the expression, 20 - 2x ?

1

20

2

2

3

x

4

a

7

Multiple Choice

What is the coefficient in the expression 3 + 4y ?

1

3

2

+

3

4

4

y

8

Multiple Choice

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1
2
3
4

9

Multiple Choice

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1
2
3
4

10

Multiple Choice

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1
2
3
4

11

Multiple Choice

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1
2
3
4

12

Multiple Choice

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1

xxx=111111x\cdot x\cdot x=1\cdot1\cdot1\cdot1\cdot1\cdot1

2

xxx=6x\cdot x\cdot x=6

3

3x = 63x\ =\ 6

4

x+3=6x+3=6

13

Multiple Choice

Question image

1

13 45=w + 3 4513\ \frac{4}{5}=w\ +\ 3\ \frac{4}{5}

2

13 45 = 3 45w13\ \frac{4}{5}\ =\ 3\ \frac{4}{5}\cdot w

14

Multiple Choice

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1

12 = 2 + y12\ =\ 2\ +\ y

2

12=2y12=2y

15

Multiple Choice

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1

3 x = 83\ \cdot\ x\ =\ 8

2

3 + x = 83\ +\ x\ =\ 8

16

Solving/Balancing

When it's all variables....

17

Solve/Balance

A variable and some numbers...

18

Solve/Balance

All variables...

19

Solve/Balance

A mix of variables and numbers...

20

Multiple Choice

Question image

Explain how to reason with the diagram to find the weight of x.

1

x and 3 together must equal 8, so x is 5 because 5 + 3 = 8

2

x and 3 together must equal 8, so x is 4 because 4 + 3 = 8

21

Multiple Choice

Question image

Which explains another way to reason what the value of x is?

1

Remove 3 from both sides to keep the hanger balanced. X is 5 since 8 - 3 is 5.

2

Remove x from both sides to keep the hanger balanced. 3 = 8

22

Multiple Choice

Question image

Explain how to reason with the diagram to find the weight of a piece with a letter.

1

y = 12. 12 is twice the weight of y, so y weighs half of 6.

2

y = 6. 12 is twice the weight of y, so y weighs half of 12.

23

Multiple Choice

Question image

Equation: 11 = 4z

Explain how to reason with the equation to find the weight of a piece with a letter.

1

Dividing each side of the equation by 4 leaves 11/4 = z.

2

Dividing each side of the equation by 2 leaves 22/4 = z .

Staying in Balance!

I can add or remove objects from each side of a hanger to keep the hanger balanced.


I can represent a hanger diagram with an equation.

Slide image

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