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Momentum and Impulse

Momentum and Impulse

Assessment

Presentation

Physics

10th - 12th Grade

Practice Problem

Easy

NGSS
HS-PS2-2

Standards-aligned

Created by

Daniel Hawboldt

Used 27+ times

FREE Resource

8 Slides • 2 Questions

1

Momentum and Impulse

Mr. Hawboldt

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2

Open Ended

Which has more momentum: An elephant walking or a fastball thrown by an MLB pitcher. Explain your reasoning

3

Momentum

  • "the impetus gained by a moving object; a product of an objects mass and velocity"

  • represented by the letter  pp  

  •  p=m×vp=m\times v  

  • has a direction and therefore CAN be negative

  • units for momentum are kilograms x meters per second or  kgmskg\cdot\frac{m}{s}  

  • opposite of less-mentum

4

Open Ended

Can a pebble have more momentum than a boulder? Explain

5

 p=m×vp=m\times v  rearranged

  •  m=pvm=\frac{p}{v}  

  •  v=pmv=\frac{p}{m}  

6

Impulse

  • "an impetus that results from a force exerted on an object over time"

  •  JJ  represented by the letter

  •  J=F×tJ=F\times t  

  • has a direction therefore CAN be negative

  • units for impulse are Newtons x seconds or  NsN\cdot s  

7

Momentum AND impulse

  • momentum is what an object has; you can see it the same way you see velocity

  • impulse is what you do; you have to act (apply a force) in order for there to be impulse

8

Follow the units

  • Units for impulse are NsN\cdot s  

  •  NN  are the units for force which come from Newton's Second Law which is  Fnet=m×aF_{net_{ }}=m\times a  

  • substituting in the units for each quantity we would see  N=kg×ms2N=kg\times\frac{m}{s^2}  

  • replace  NN  in the units for impulse with  kgms2kg\cdot\frac{m}{s^2}  and get

  •  (kgms2)s\left(kg\cdot\frac{m}{s^2}\right)\cdot s  

  •  ss  cancels out another  ss   which gives the final form of  kgmskg\cdot\frac{m}{s}  

9

Impulse can be found by finding the CHANGE in momentum (Δp)\left(\Delta p\right) 

  • in equation form this looks like:  J=ΔpJ=\Delta p  

  • change in momentum is the difference in momenta or \Delta p=p_f-p_i  

  • combining the last two lines gives:  J=pfpiJ=p_f-p_i  

  • Just like the Work-Energy Theorem, impulse "adds" momentum to a system

10

Summary

  • momentum (p)\left(p\right)  depends on mass and velocity and includes direction  

  •  p=m×vp=m\times v  

  • Impulse  (J)\left(J\right)  is an applied force over a period of time

  •  J=F×tJ=F\times t  

  • Impulse can be found by finding the change in momentum

  •  J=ΔpJ=\Delta p  OR J=pfpiJ=p_f-p_i  

Momentum and Impulse

Mr. Hawboldt

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