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Ch10 Review

Ch10 Review

Assessment

Presentation

Mathematics

9th - 12th Grade

Medium

CCSS
HSG.GPE.A.1, 5.G.A.1

Standards-aligned

Created by

Paige Vanderbosch

Used 12+ times

FREE Resource

4 Slides • 13 Questions

1

Geometry

Chapter 10 Review

Slide image

2

Chapter 10

Lesson 10.1 - Properties of Circles

Lesson 10.2 - Equations of Circles

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Lesson 10.1

  • Center

  • Radius

  • Diameter

  • Chord

  • Secant

  • Tangent & Common Tangent

  • Point of Tangency

4

Multiple Choice

Choose the image that shows a RADIUS.

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Multiple Choice

Choose the image that shows a SECANT.

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Multiple Choice

Choose the image that shows a TANGENT.

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Multiple Choice

Choose the image that shows a DIAMETER.

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Multiple Choice

Choose the image that shows a CHORD.

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9

Multiple Choice

Question image

What is the center of the circle?

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Q

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T

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P

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PS\overline{PS}

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TN\overline{TN}

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Multiple Choice

Question image

In the diagram given, identify the point of tangency.

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Q

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P

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W

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PS\overline{PS}

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 TV\overline{TV} 

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Lesson 10.2

  •  (xh)2+(yk)2=r2\left(x-h\right)^2+\left(y-k\right)^2=r^2  

  • Center =  (h, k)\left(h,\ k\right)  

  • Radius =  rr  

12

Fill in the Blanks

media image

Type answer...

13

Multiple Choice

Question image

What is the center of the circle?

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(1, -4)

2

(-4, 1)

3

(-1, 4)

4

(4, -1)

14

Multiple Choice

What is the equation of a circle with a center at (-7, 5) and a radius of 4?

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(x7)2+(y+5)2=4\left(x-7\right)^2+\left(y+5\right)^2=4

2

(x+7)2+(y5)2=16\left(x+7\right)^2+\left(y-5\right)^2=16

3

(x5)2+(y+7)2=16\left(x-5\right)^2+\left(y+7\right)^2=16

4

(x+5)2+(y7)2=4\left(x+5\right)^2+\left(y-7\right)^2=4

15

Multiple Choice

What is the equation of a circle with a center at (3, -1) and a radius of 5?

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 (x+3)2+(y1)2=5\left(x+3\right)^2+\left(y-1\right)^2=5 

2

 (x3)2+(y+1)2=25\left(x-3\right)^2+\left(y+1\right)^2=25 

3

 (x1)2+(y+3)2=25\left(x-1\right)^2+\left(y+3\right)^2=25 

4

 (x+1)2+(y3)2=4\left(x+1\right)^2+\left(y-3\right)^2=4 

16

Multiple Choice

Choose the circle that has the equation  (x+3)2+(y3)2=9\left(x+3\right)^2+\left(y-3\right)^2=9  

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17

Poll

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Geometry

Chapter 10 Review

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